roulette mathmatically proven maybe

the average number of unique numbers to come out in 36 spins is 25. that means if you randomly pick a number and bet on it till you win or a maximum of 36 times you will win 25 times out of 36. which means you will win 69.44 % of the time and loose 30.56% of the time or slightly over 2 wins to 1 loss your average return should be 50% of your stake for example 1 unit per spin upto a total of 36 units on average should return 18 units this should happen just over twice (2.78% more) and you should loose once so you loose say 36 units but win 18 units twice plus 2.78%. its just a theory obviously roulette is completely random but the law of big numbers (the more times you play) should bring you close to that result

Your loosing sessions will wipe out the winning sessions.

if you do it 10,000 times you should win 18 units 6,944 times +124,992 units and loose 36 units 3,056 times 110,016 units. so you should make 14,976 units

Quote: chaosrevolt

if you do it 10,000 times you should win 18 units 6,944 times +124,992 units and loose 36 units 3,056 times 110,016 units. so you should make 14,976 units

Hi Chaos,
I have a few minutes to spare, in which to do the maths to prove you mind-crushingly wrong, but before I commence, please define which version of roulette you are making this assertion for?

Quote: chaosrevolt

the average number of unique numbers to come out in 36 spins is 25. that means if you randomly pick a number and bet on it till you win or a maximum of 36 times you will win 25 times out of 36.

Er, no, it does not.

By my calculation, you will lose an average of about 1.234 units per "run."

european

If you number hits (once) then you break even. How's that winning?

ive been using /simulator/?mode=martingale&sess=MEDUD2GA
and refreshing after every win (you have to load another system simulator and then return to refresh) spins 36 progression factor 0 go home after 1 win if i lose i generate another number without refreshing (choosing numbers on googles random number generator) and i am +263 units. the most i have been down is 81 units.

Sounds like you have a mighty fine system then, I guess. Idk. Go use it at the casino then? Let us know how it works!

Hey everybody, I just realized something.

If you bet on the underdog in football and they win, you win
If you bet on the underdog and they cover, you win
If you bet on the underdog and they do not cover, you lose

Hence, if you bet on the underdog you will win 2/3 of the time and PROFIT

Quote: RS

Sounds like you have a mighty fine system then, I guess. Idk. Go use it at the casino then? Let us know how it works!

He'll lie just like every other roulette system player.

Quote: Ibeatyouraces

He'll lie just like every other roulette system player.

What? You mean you think these guys are lying!? Why would someone lie???

If you go with 38 spins instead of 36 (There are 38 numbers on the wheel), you will see where your math breaks down. Sorry.

Quote: FCBLComish

If you go with 38 spins instead of 36 (There are 38 numbers on the wheel), you will see where your math breaks down. Sorry.

He's playing single zero roulette: 37 numbers.
But don't worry. His is just another fun way to lose 1/37x(whatever he lays on the table) give or take a bit of variance.

Quote: chaosrevolt

... randomly pick a number and bet on it till you win ... you will win 25 times out of 36...over 2 wins to 1 loss your average return should be 50% of your stake .... the law of big numbers (the more times you play) should bring you close to that result

ah, we love the roulette players and their thinking

this person, however, is so wildly flinging the stuff around you have to wonder how he could believe it himself. If he actually plays roulette, he would soon be disabused of the idea that he will win two times for every session loss

I would say the Wizard is maybe right about wanting to sell a system, but he lays it all out here how to do it

i thought this was a forum for betting systems. i am not lying or trying to sell anything this me putting an idea out for free you dont have to try it maybe it works maybe it doesnt. but all the numbers i come up with suggest it will. practice is obviously very different from theory. just because the average number of times a unique number comes out is 25 doesnt mean an individual will see it happen. on every bet there has to be winners or losers the truth is you are born a winner or a loser you need to create opportunity to find out which one you are. you can do the same theory with 37 spins average number of unique numbers is nearer to 26 increasing your chance of winning. the math is very simple. if you win 25 times out of 36 or 25 times out of 37 you should still win a tiny percentage more than 66.666% of the time. your average winnings the more times you play should be close to 50% of the stake. if your stake is 36 units you could lose that in one go or you could win 35 units 100 times however unlikely that is it is possible as with any combination of bets.

Quote: chaosrevolt

the math is very simple. if you win 25 times out of 36 or 25 times out of 37 you should still win a tiny percentage more than 66.666% of the time.

That is true - however, "the average number of unique numbers in 36 spins is 25" and "any particular number has a 25/36 chance of coming up in a group of 36 consecutive spins" are two entirely different statements.

The probability of a number not coming up on a single-zero wheel in one spin is 36/37.
The probability of a particular number not coming up in 36 consecutive spins is (36/37)³⁶ = 0.37293, or slightly less than 3/8.
Thus, the probability of a particular number coming up at least once in 36 consecutive spins is slightly more than 5/8, but definitely less than 25/36.
Even if we go by "a win gains 18 on average" and a loss loses 36, you win 18 5/8 of the time and lose 36 8/8 of the time, which is a net loss.