stoneeagle
Posted by stoneeagle
Jul 08, 2012

Blackjack, Insurance Bet Question

In double deck Blackjack, I play basic strategy and also use a perfect insurance count. The count starts at zero, then add 1 for each non-Ten, and subtract 2 for each Ten. If the count is greater than +8, take insurance. The penetration is about 60%. How often will the count exceed +8 and what will be the average player advantage at these times?

Recently I played when the count exceeded +8 for two consecutive hands. I took insurance on the first hand and won the bet. On the second hand, I had a Blackjack, and took “even money”. The dealer did not have Blackjack. I think I made the right decision on the second hand. My friend said no… I made the decision for a lower expected value. Is he right?

Comments

Ibeatyouraces
Ibeatyouraces Jul 08, 2012

You should have posted this in the forums but if the count warrants insurance than you take it irregardless of what your hand is. If the count was right to take "even money" then yes, you made the right call and will make more money by doing so in the right situation.

DJTeddyBear
DJTeddyBear Jul 13, 2012

>> I made the decision for a lower expected value.



What does that mean?



For the record, taking even money is exactly the same as playing the insurance bet.