EZ Baccarat probability question

Given the EZ baccarat probabilities of .446279 for the player, .436118 for the banker, .095069 for a tie, and .022535 for the dragon, what would the probability/expected return be for the following bet: $20 on either the banker or the player along with a $10 bet on the tie (or any other scenario where the tie bet is half of your player or banker bet). I'm curious as to what this would yield if bet consistently and how it would compare to the house edge.

For clarification tie pays 8 to 1 and when a dragon occurs the bank bet pushes and player bet loses. Also 0% commission on banker bet.

In E-Z Baccarat the House Edge on the Bank is reduced ever so slightly.

1.0.6% to 1.0.3%

Quote: ZenMasterFlash

In E-Z Baccarat the House Edge on the Bank is reduced ever so slightly.

1.0.6% to 1.0.3%

1.02% (actually 1.0183%).

Quote: smz337

Given the EZ baccarat probabilities of .446279 for the player, .436118 for the banker, .095069 for a tie, and .022535 for the dragon, what would the probability/expected return be for the following bet: $20 on either the banker or the player along with a $10 bet on the tie (or any other scenario where the tie bet is half of your player or banker bet). I'm curious as to what this would yield if bet consistently and how it would compare to the house edge.

The house edge with 2/3 on Banker and 1/3 on Tie is (2/3)*1.018% + (1/3)*14.360% = 5.47%.
The house edge with 2/3 on Player and 1/3 on Tie is (2/3)*1.235% + (1/3)*14.360% = 5.61%.

1.02% (actually 1.0183%).

Eliot is probably correct !

Quote: ZenMasterFlash

Eliot is probably correct !

Yes, with probability = 1.