JLFearless
JLFearless
Joined: Apr 20, 2011
  • Threads: 1
  • Posts: 1
April 20th, 2011 at 7:55:47 AM permalink
I'd like to know the math behind figuring the number of Wild combinations
for each Pair (2 of a Kind). I realize that for many of the lower pairs, there
are no Wild combinations. For example, if the hand is

3H,3C,4D,7H,9S

then there are no possibilities of making a Pair of 3's if the Joker were to
replace any of the cards.

I need the math broken down to the point to where I can calculate each
possible pair, and then, based on percentages, divide the possible pairs.
For example, I may divide the pairs into

"Jacks or Better" and "10's or lower" OR "9's or Better" and "8's or lower"
DJTeddyBear
DJTeddyBear
Joined: Nov 2, 2009
  • Threads: 174
  • Posts: 10045
April 20th, 2011 at 9:04:27 AM permalink
As I recently found out, and has been confirmed by MathExtremist, once wilds are involved, the easiest / best method is to simply cycle thru every possible combination and evaluate them individually.
Superstitions are silly, childish, irrational rituals, born out of fear of the unknown. But how much does it cost to knock on wood? 😁 Note that the same could be said for Religion. I.E. Religion is nothing more than organized superstition. 🤗

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