JLFearless
JLFearless
Joined: Apr 20, 2011
  • Threads: 1
  • Posts: 1
April 20th, 2011 at 7:55:47 AM permalink
I'd like to know the math behind figuring the number of Wild combinations
for each Pair (2 of a Kind). I realize that for many of the lower pairs, there
are no Wild combinations. For example, if the hand is

3H,3C,4D,7H,9S

then there are no possibilities of making a Pair of 3's if the Joker were to
replace any of the cards.

I need the math broken down to the point to where I can calculate each
possible pair, and then, based on percentages, divide the possible pairs.
For example, I may divide the pairs into

"Jacks or Better" and "10's or lower" OR "9's or Better" and "8's or lower"
DJTeddyBear
DJTeddyBear
Joined: Nov 2, 2009
  • Threads: 191
  • Posts: 10547
April 20th, 2011 at 9:04:27 AM permalink
As I recently found out, and has been confirmed by MathExtremist, once wilds are involved, the easiest / best method is to simply cycle thru every possible combination and evaluate them individually.
I invented a few casino games. Info: http://www.DaveMillerGaming.com/ 覧覧覧覧覧覧覧覧覧覧覧覧覧覧覧覧覧覧 Superstitions are silly, childish, irrational rituals, born out of fear of the unknown. But how much does it cost to knock on wood? 😁

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