ssho88
ssho88
Joined: Oct 16, 2011
  • Threads: 52
  • Posts: 625
August 6th, 2022 at 7:33:55 AM permalink
Quote: unJon

Quote: ssho88

Here is the integral solution:-



However, I think that series only converge if -1 < x < 1. So I think still not able to find length of arc 1/x from x = 1 to x = 3. Any comment?
link to original post



Just the same comment I made twice before.

https://www.wolframalpha.com/input?i=arc+length+1%2FX&assumption=%7B%22F%22%2C+%22ArcLength%22%2C+%22a%22%7D+-%3E%221%22&assumption=%7B%22F%22%2C+%22ArcLength%22%2C+%22b%22%7D+-%3E%223%22
link to original post



Thanks for your reply.

So Taylor series is not a viable way to find the arc length of 1/x ?
unJon
unJon
Joined: Jul 1, 2018
  • Threads: 14
  • Posts: 3552
August 6th, 2022 at 8:09:39 AM permalink
Quote: ssho88

Quote: unJon

Quote: ssho88

Here is the integral solution:-



However, I think that series only converge if -1 < x < 1. So I think still not able to find length of arc 1/x from x = 1 to x = 3. Any comment?
link to original post



Just the same comment I made twice before.

https://www.wolframalpha.com/input?i=arc+length+1%2FX&assumption=%7B%22F%22%2C+%22ArcLength%22%2C+%22a%22%7D+-%3E%221%22&assumption=%7B%22F%22%2C+%22ArcLength%22%2C+%22b%22%7D+-%3E%223%22
link to original post



Thanks for your reply.

So Taylor series is not a viable way to find the arc length of 1/x ?
link to original post



I donít know. Havenít used Taylor series since college. Wolfram seems to think itís a Puiseux type series.

https://www.wolframalpha.com/input?i=Taylor+%281+%2B+1%2Fx%5E4%29%5E0.5
The race is not always to the swift, nor the battle to the strong; but that is the way to bet.

  • Jump to: