Bob
If you want exactly 8 of the same number (as opposed to 8 or more), but it can be any number:
(a) There are 6 possibilities for the number (e.g. eight 1s, or eight 6s)
(a) There are 10C2 = 45 ways of selecting the two dice that are not in the 8 of a kind;
(b) There are 5 different numbers that the "first" of these two dice can be;
(c) There are 5 different numbers that the "second" of these two dice can be;
There are a total of 6 * 45 * 5 * 5 = 6750 different rolls that can be eight of a kind, out of the 610 = 60,466,176 different possible rolls; the probability is 1 in (60,466,176 / 6750) = 1 in 8958. This is one of the formulas you found.
If you want a specific 8 of a kind (e.g. it has to be eight 6s), then ignore (a) in the above, so there are only 1125 possible rolls, and the probability is 1 in (60,466,176 / 1225) = 1 in 53,748.
I am not sure where you got "37,000 to 1."
PS is it correct to match 8 of a kind on one shake with 8 dice is 6 to the 8th power? If correct is that for a specific number or any 8 of a kind?
Bob
Quote: RltkktlrHow would it look if I wanted 8 or more? i really became curious when I was at a place in WI that had a pot up to $10k if matched 8 out of 10 with 1 shake. Thanks again.
Is it correct to match 8 of a kind on one shake with 8 dice is 6 to the 8th power? If correct is that for a specific number or any 8 of a kind?
To calculate 8 or more, calculate 8, 9, and 10 separately, and then add them up.
9 of a kind is 6 (there are 6 different numbers that the 9 of a kind can be) * 10C1 (since you need to choose the one die that isn't in the 9 of a kind) * 5 (since there are 5 possible numbers it can be) = 450.
(You can also use 6 * 10C9 (to choose the 9 dice in the 9 of a kind rather than the 1 die that's not in it) * 5; this is also 450. Note that nCr = nC(n-r), since there are just as many ways to choose r items out of n as there are "not to choose" (n-r) items out of n - for every set of r items you choose, there is a corresponding set of (n-r) items that you did not choose.)
8 of a kind out of 8 with one shake is 1 in 68 for a specific number, or 6 times that for any 8 of a kind. There are 68 ways to roll 8 dice; one of them is, say, eight 6s, and six of them (1s, 2s, 3s, 4s, 5s, 6s) are 8 of a kind.
I think I have used this one before
http://blog.plover.com/math/yahtzee.html
He also does a nice job of explaining how to count the number of different ways of rolling a certain
pattern of numbers with a certain number of dice
The distribution is this for 10d6 patterns
pattern | ways | probability |
---|---|---|
AABBCCDDEF | 3,402,000 | 0.05626286 |
AABBCCDDEE | 680,400 | 0.011252572 |
AAABBCCDEF | 9,072,000 | 0.150034294 |
AAABBCCDDE | 9,072,000 | 0.150034294 |
AAABBBCDEF | 1,512,000 | 0.025005716 |
AAABBBCCDE | 9,072,000 | 0.150034294 |
AAABBBCCDD | 2,268,000 | 0.037508573 |
AAABBBCCCD | 1,008,000 | 0.016670477 |
AAAABBCDEF | 2,268,000 | 0.037508573 |
AAAABBCCDE | 6,804,000 | 0.11252572 |
AAAABBCCDD | 1,134,000 | 0.018754287 |
AAAABBBCDE | 3,024,000 | 0.050011431 |
AAAABBBCCD | 4,536,000 | 0.075017147 |
AAAABBBCCC | 252,000 | 0.004167619 |
AAAABBBBCD | 567,000 | 0.009377143 |
AAAABBBBCC | 189,000 | 0.003125714 |
AAAAABCDEF | 181,440 | 0.003000686 |
AAAAABBCDE | 1,814,400 | 0.030006859 |
AAAAABBCCD | 1,360,800 | 0.022505144 |
AAAAABBBCD | 907,200 | 0.015003429 |
AAAAABBBCC | 302,400 | 0.005001143 |
AAAAABBBBC | 151,200 | 0.002500572 |
AAAAABBBBB | 3,780 | 6.25143E-05 |
AAAAAABCDE | 151,200 | 0.002500572 |
AAAAAABBCD | 453,600 | 0.007501715 |
AAAAAABBCC | 75,600 | 0.001250286 |
AAAAAABBBC | 100,800 | 0.001667048 |
AAAAAABBBB | 6,300 | 0.00010419 |
AAAAAAABCD | 43,200 | 0.000714449 |
AAAAAAABBC | 43,200 | 0.000714449 |
AAAAAAABBB | 3,600 | 5.95374E-05 |
AAAAAAAABC | 5,400 | 8.93061E-05 |
AAAAAAAABB | 1,350 | 2.23265E-05 |
AAAAAAAAAB | 300 | 4.96145E-06 |
AAAAAAAAAA | 6 | 9.9229E-08 |
total | 60,466,176 | 1 |
Don made a SallyOh error for the 9oak. should = 300 (6*10*5)
super high house edge for the game you saw!
Sally
a shake
I love chocolate shakes and so do my hips and thighs
here is a shake game I found too
at least it is not this game
Bob
Bob
Ps sorry again just trying to learn what I should have learned in collage!
you are so close.Quote: RltkktlrNot sure how to plug 300 into original formula. Or would it be 900 (300 for 8,9,10) anyway not sure what to do with the 300(900). Need to know next step.
took me a few years to finally get this type of math
Don might have been doing these dice problems as a two year old. Some are so lucky!
The link I also provided I thought really explains well how to solve these type of pattern problems.
here
what you need to understand is the pattern
your example:
AAAA AAAABC: 5400 ways
Is one way to get 8oak with 2 singletons for the other two dice
AAAA AAAABB:1350
Is another way to get 8oak with a pair for the other two dice
AAAA AAAA AB: 300
the only way to get 9oak
A can bet any of 6 values
B can be any of 5 values
because we Have 10 and Want 9oak 10C9 = 10
6*5*10=300
AAAA AAAA AA: 6
so for any 8,9 or 10oak we sum each possible pattern
that should be clear
one more example
AAAA AAAABC: 5400 ways
we Have 10 and Want 8oak = 10C8 = 10! / 8! (10-2)! = 10*9/2*1 = 45
A could be any 6 values
B must be 5 values
C must be 4 values
45*6*5*4
This is really high school math.Quote: RltkktlrAlso to help me with further understanding, back to matching any 8 of a kind but this time shaking 12 dice? I tried what I thought was maybe correct and came up with about 1 in 36. Seems way off. Thanks again.
Bob
Ps sorry again just trying to learn what I should have learned in collage!
maybe with the kids today, grade school even.
here is the table for the 12 dice
pattern | ways | probability |
---|---|---|
AABBCCDDEEFF | 7,484,400 | 0.003438286 |
AAABBCCDDEEF | 149,688,000 | 0.068765718 |
AAABBBCCDDEF | 299,376,000 | 0.137531436 |
AAABBBCCDDEE | 99,792,000 | 0.045843812 |
AAABBBCCCDEF | 44,352,000 | 0.020375028 |
AAABBBCCCDDE | 133,056,000 | 0.061125083 |
AAABBBCCCDDD | 5,544,000 | 0.002546878 |
AAAABBCCDDEF | 149,688,000 | 0.068765718 |
AAAABBCCDDEE | 37,422,000 | 0.017191429 |
AAAABBBCCDEF | 199,584,000 | 0.091687624 |
AAAABBBCCDDE | 299,376,000 | 0.137531436 |
AAAABBBCCCDE | 99,792,000 | 0.045843812 |
AAAABBBCCCDD | 49,896,000 | 0.022921906 |
AAAABBBBCDEF | 12,474,000 | 0.005730476 |
AAAABBBBCCDE | 74,844,000 | 0.034382859 |
AAAABBBBCCDD | 18,711,000 | 0.008595715 |
AAAABBBBCCCD | 24,948,000 | 0.011460953 |
AAAABBBBCCCC | 693,000 | 0.00031836 |
AAAAABBCCDEF | 59,875,200 | 0.027506287 |
AAAAABBCCDDE | 59,875,200 | 0.027506287 |
AAAAABBBCDEF | 19,958,400 | 0.009168762 |
AAAAABBBCCDE | 119,750,400 | 0.055012574 |
AAAAABBBCCDD | 29,937,600 | 0.013753144 |
AAAAABBBCCCD | 19,958,400 | 0.009168762 |
AAAAABBBBCDE | 19,958,400 | 0.009168762 |
AAAAABBBBCCD | 29,937,600 | 0.013753144 |
AAAAABBBBCCC | 3,326,400 | 0.001528127 |
AAAAABBBBBCD | 2,993,760 | 0.001375314 |
AAAAABBBBBCC | 997,920 | 0.000458438 |
AAAAAABBCDEF | 9,979,200 | 0.004584381 |
AAAAAABBCCDE | 29,937,600 | 0.013753144 |
AAAAAABBCCDD | 4,989,600 | 0.002292191 |
AAAAAABBBCDE | 13,305,600 | 0.006112508 |
AAAAAABBBCCD | 19,958,400 | 0.009168762 |
AAAAAABBBCCC | 1,108,800 | 0.000509376 |
AAAAAABBBBCD | 4,989,600 | 0.002292191 |
AAAAAABBBBCC | 1,663,200 | 0.000764064 |
AAAAAABBBBBC | 665,280 | 0.000305625 |
AAAAAABBBBBB | 13,860 | 6.3672E-06 |
AAAAAAABCDEF | 570,240 | 0.000261965 |
AAAAAAABBCDE | 5,702,400 | 0.002619646 |
AAAAAAABBCCD | 4,276,800 | 0.001964735 |
AAAAAAABBBCD | 2,851,200 | 0.001309823 |
AAAAAAABBBCC | 950,400 | 0.000436608 |
AAAAAAABBBBC | 475,200 | 0.000218304 |
AAAAAAABBBBB | 23,760 | 1.09152E-05 |
AAAA AAAABCDE | 356,400 | 0.000163728 |
AAAA AAAABBCD | 1,069,200 | 0.000491184 |
AAAA AAAABBCC | 178,200 | 8.18639E-05 |
AAAA AAAABBBC | 237,600 | 0.000109152 |
AAAA AAAABBBB | 14,850 | 6.822E-06 |
AAAA AAAA ABCD | 79,200 | 3.6384E-05 |
AAAA AAAA ABBC | 79,200 | 3.6384E-05 |
AAAA AAAA ABBB | 6,600 | 3.032E-06 |
AAAA AAAA AABC | 7,920 | 3.6384E-06 |
AAAA AAAA AABB | 1,980 | 9.09599E-07 |
AAAA AAAA AAAB | 360 | 1.65382E-07 |
AAAA AAAA AAAA | 6 | 2.75636E-09 |
totals | 2,176,782,336 | 1 |
for 8oak there looks to be 5 patterns (that to me is the hard part just accounting for each pattern that could be thrown - that is why the letters are used and why I use the computer)
look at each pattern and see if you can do the math for each pattern
AAAA AAAA BCDE
start with you Have 12 and Want 8 = 12C8
Now you have 4 and want ?
go until you have none left
the value each letter could be how many and multiply them all for each
then sum them up from all the number of patterns
if you really want to learn this, try using 3 or 4 dice to start
that way you can see quickly how you are doing and it will build confidence.
have fun!
Sally
Bob.
Ps could be more questions but not until I study!