Quote:A German 16-year-old has become the first person to solve a mathematical problem posed by Sir Isaac Newton more than 300 years ago.

Shouryya Ray worked out how to calculate exactly the path of a projectile under gravity and subject to air resistance, The (London) Sunday Times reported.

http://www.foxnews.com/world/2012/05/27/german-teen-solves-300-year-old-mathematical-riddle-posed-by-sir-isaac-newton/#ixzz1wPczbNtj

Sort of sad that it will improve the field of ballistics...

When is someone going to figure out how the world can cough up a few billion to end starvation?

Quote:WongBoItWhen is someone going to figure out how the world can cough up a few billion to end starvation?

How about figuring out how to stop idiots who can't

afford it from having too many babies first.

Quote:EvenBobHow about figuring out how to stop idiots who can't

afford it from having too many babies first.

http://www.latimes.com/news/nation/nationnow/la-na-nn-tennessee-man-has-30-kids-20120518,0,4036567.story

A math genius born in India. I'm sure Germany is very proud..

Many American have German heritage.

One thing they have in common,

Claiming the successful citizens as their own.

If this guy had shot up a school,

The headline would read "Indian immigrant shoots...

Quote:WongBoYou know the Germans are a lot like Americans,

If it was America and it was a first gen Chinese kid

named Lee Chang, I can almost guarantee it would

have been reported as 'Chinese-American Lee Chang'.

But if he was a white/euro it would just say American..

what question exactly did he solve?

Quote:andysifi have been searching the whole internet with no answer.

what question exactly did he solve?

Why 5 pounds of cement won't fit is a 3 pound

bucket has always baffled me. It probably

something harder than that, though..

which physicists have previously been able to calculate only by using powerful computers.

The first problem is: “Particle-wall collision under Hertzian collision force and linear Damping.”

And the second problem is: “Trajectory of an oblique body thrown in the earth’s gravitational field

and Newton’s law of universal gravitation to calculate Flow resistance.":

Let (x(t),y(t)) be the position of a particle at time t.

Let g be the acceleration due to gravity and c the constant of friction.

Solve the differential equation:

(x''(t)^2 + (y''(t)+g)^2 )^{1/2} = c(x'(t)^2 + y'(t)^2 )

subject to the constraint that (x''(t),y''(t)+g) is always opposite in direction to (x'(t),y'(t)).

Finding the general solution to this differential equation will find the general solution

for the path of a particle which has drag proportional to the square of the velocity (and opposite in direction).

Here's an explanation how this differential equation encodes the motion of such a particle:

The square of the velocity is:

x'(t)^2 + y'(t)^2

The total acceleraton is:

( x''(t)^2 + y''(t)^2 )^{1/2}

The acceleration due to gravity is g in the negative y direction.

Thus the drag (acceleration due only to friction) is [the preceding should probably read

"the impedance (acceleration due to friction plus gravity) is"]:

\bigg( x''(t)2 + (y''(t)+g)2 \bigg)(1/2)

Thus path of such a particle satisfies the differential equation:

( x''(t)^2 + (y''(t)+g)^2 )^{1/2} = c(x'(t)^2 + y'(t)^2 )

Of course, we also require the direction of the drag (x''(t),y''(t)+g)

to be opposite to the direction of the velocity (x'(t),y'(t)).

Once we find the intial position and velocity of the particle,

uniqueness theorems tell us its path is uniquely determined."

"Here's a forward solution (found by reverse-engineering the answer):

Consider a projectile moving in gravity with quadratic air resistance.

The governing equations are

u' = -a u \sqrt{ u^2 + v^2 }

v' = -a v \sqrt{ u^2 + v^2 } - g

where a is the coefficient of air resistance defined by |F| = ma|v|^2 .

Cross-multiply and rearrange to find

a \sqrt{ u^2 + v^2 } (uv'-vu') = gu'

Substitute v = su and separate variables:

a \sqrt{ 1 + s^2} s' = g\frac {u'}{u^3}

Integrate both sides to get the answer:

\frac g {u^2} + a \left(\frac{v \sqrt{ u^2 + v^2 }}{u^2} + \sinh^{-1}\left|\frac v u\right| \right)= C"

2. Teach him to count cards at blackjack.

3. ???

4. Profit!!!

Quote:konceptum1. Find German teen.

2. Teach him to count cards at blackjack.

3. ???

4. Profit!!!

This is stupid. The mathematical part of card counting is easy. It's everything else that is hard, and I'm guessing the kid's social skills aren't in the same realm as his math skills.

Quote:WongBoSort of sad that it will improve the field of ballistics...

Not sad at all. Doping the wind will still be art.

Quote:AcesAndEightsThis is stupid. The mathematical part of card counting is easy.

The movie Rainman was stupid, as are most BJ movies.

Totally out of whack with reality. The latest is on the

TV show Breaking Bad. The main guy makes millions

by cooking meth, and his wife explains the money as

winnings from card counting BJ. Everybody buys it,

even the audience. Nobody on the shows discussion

boards even raised an eyebrow, movies have convinced

them wealth is easily attainable this way.

Quote:rxwineQuote:A German 16-year-old has become the first person to solve a mathematical problem posed by Sir Isaac Newton more than 300 years ago.

I'm curious about how long it will take someone to find his error.

Quote:AcesAndEightsThis is stupid. The mathematical part of card counting is easy. It's everything else that is hard, and I'm guessing the kid's social skills aren't in the same realm as his math skills.

That's why the number 3 is in question marks. Figure out the hard part, and the profit is easy to come by.

But, ultimately, I figured more people would recognize the meme. I was wrong.