thezone
Joined: Nov 19, 2012
• Posts: 43
January 3rd, 2013 at 7:20:34 PM permalink
Can anyone figure out the strategy of how to play with roughly 66% probability of winning on each bet? It can be done in two games of my choice. One bet has a 16% chance of losing the other has roughly 35% chance of losing. Risk, however, is not 1 to 1.
sodawater
Joined: May 14, 2012
• Posts: 3321
January 3rd, 2013 at 7:27:39 PM permalink
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Last edited by: sodawater on Oct 1, 2018
thezone
Joined: Nov 19, 2012
• Posts: 43
January 3rd, 2013 at 7:29:08 PM permalink
Never tried that... but interesting!
MakingBook
Joined: Sep 19, 2011
• Posts: 496
January 3rd, 2013 at 7:31:46 PM permalink
Quote: thezone

Can anyone figure out the strategy of how to play with roughly 66% probability of winning on each bet?

Hell, that's easy. Just fade my picks in the WoV picks game. You must have seen my W/L record.
"I am a man devoured by the passion for gambling." --Dostoevsky, 1871
sodawater
Joined: May 14, 2012
• Posts: 3321
January 3rd, 2013 at 7:38:58 PM permalink
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Last edited by: sodawater on Oct 1, 2018
sodawater
Joined: May 14, 2012
• Posts: 3321
January 3rd, 2013 at 7:40:02 PM permalink
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Last edited by: sodawater on Oct 1, 2018
thezone
Joined: Nov 19, 2012
• Posts: 43
January 3rd, 2013 at 7:49:30 PM permalink
Correct with option 3... play any 2 of the 3 blocks (1st 12, 2nd 12, 3rd 12) . As far as option 2 goes, you dont have a 66% chance of winning on every roll.. laying 2 to 1 with probability of 50% over a series of rolls until either hits.
thezone
Joined: Nov 19, 2012
• Posts: 43
January 3rd, 2013 at 7:50:44 PM permalink
not to mention the house juice.. which is 5%
sodawater
Joined: May 14, 2012