scepticus
scepticus
Joined: Oct 16, 2013
  • Threads: 4
  • Posts: 57
February 12th, 2014 at 8:37:50 PM permalink
What is my Edge in Roulette ?
Leaving aside the zero / s for the moment.
If I bet only one column in two dozens I bet 8 numbers. This is 1/3 x 2/3 and if I win I get paid correct odds of 7 / 2.
The chance of choosing any 2 dozens from 3 is 1 in 3 , but what if I could get this down to 1 in 2 ? After factoring in the 1 zero or 2 zeros what edge do I have ?
Thanks.
Tomspur
Tomspur
Joined: Jul 12, 2013
  • Threads: 28
  • Posts: 2019
February 12th, 2014 at 8:48:55 PM permalink
Quote: scepticus

What is my Edge in Roulette ?
Leaving aside the zero / s for the moment.
If I bet only one column in two dozens I bet 8 numbers. This is 1/3 x 2/3 and if I win I get paid correct odds of 7 / 2.
The chance of choosing any 2 dozens from 3 is 1 in 3 , but what if I could get this down to 1 in 2 ? After factoring in the 1 zero or 2 zeros what edge do I have ?
Thanks.



Not sure I udnerstand you 100% but as far as I know you can never alter the HE on Roulette unless you cheat. It will always be 5.26% for double zero and 2.7% for single zero, no matter what you do.

If you have a biased wheel or you cheat then you could make a difference. No betting system I know of can change the numbers.

Not sure I answered you but I did the best I could.
“There is something about the outside of a horse that is good for the inside of a man.” - Winston Churchill
EvenBob
EvenBob
Joined: Jul 18, 2010
  • Threads: 434
  • Posts: 25333
February 12th, 2014 at 8:54:11 PM permalink
No matter what convoluted combo of bets you
come up with, the edge never changes. All
bets in roulette are the same, the layout is
an illusion. The basket bet has different HE,
it's higher. Look at the layout as a math game,
a puzzle where the answer is always the same
no matter where you bet. You lose at the HE.
"It's not enough to succeed, your friends must fail." Gore Vidal
scepticus
scepticus
Joined: Oct 16, 2013
  • Threads: 4
  • Posts: 57
February 12th, 2014 at 8:54:18 PM permalink
Thanks Tomspur and Evenbob
Just regard it as a maths question with no preconceptions.
FleaStiff
FleaStiff
Joined: Oct 19, 2009
  • Threads: 265
  • Posts: 14484
February 12th, 2014 at 10:37:44 PM permalink
Quote: scepticus

but what if I could get this down to 1 in 2 ? After factoring in the 1 zero or 2 zeros what edge do I have ?
Thanks.



But nothing. The casino has the edge. It is 5.26 percent against you. No matter what sort of "but what if" you come up with.
You can not eliminate one of the dozens by sound of the wheel or something and then bet on the other two.

The answer is 5.26 percent whether you want to hear that answer or not. Its 5.26 percent. That's all she wrote. 5.26 percent.
endermike
endermike
Joined: Dec 10, 2013
  • Threads: 7
  • Posts: 584
February 13th, 2014 at 7:00:50 AM permalink
http://wizardofodds.com/games/roulette/

This link should give you a bit more of what you are lookng for. If you still have questions after reading that, come back and pose the question again.
scepticus
scepticus
Joined: Oct 16, 2013
  • Threads: 4
  • Posts: 57
February 13th, 2014 at 8:42:18 AM permalink
Thanks Endermike but I had already read that article- and many more.
So, come on Guys, give me the answer to my question.
Please !
Pretty Please !!??
endermike
endermike
Joined: Dec 10, 2013
  • Threads: 7
  • Posts: 584
February 13th, 2014 at 8:57:03 AM permalink
Please re phrase your question it is clear to me what you were asking. Is it something related to being able to eliminate possible outcomes and then calculating the HE based on this restricted set of possible outcomes?
scepticus
scepticus
Joined: Oct 16, 2013
  • Threads: 4
  • Posts: 57
February 13th, 2014 at 10:00:32 AM permalink
Yes.
If 2 from 3 can be reduced to 1 in 2 what is the edge.?
endermike
endermike
Joined: Dec 10, 2013
  • Threads: 7
  • Posts: 584
February 13th, 2014 at 10:21:20 AM permalink
Ignoring HE for the moment, on a 1 out of 3 bet you should be paid 3 for every 1 you bet. Assuming a 2:1 payout, on a 1 out 2 event your edge is: 50%.
(+2)*.5+(-1)*.5=+.5

Adding in zeros:
1 zero: (+2)*(12/25+(-1)*(13/25)=11/25=44.0%
2 zero: (+2)*(12/26+(-1)*(14/26)=10/26=38.5%

  • Jump to: