I would guess you would keep the "high pair only" in this situation, but I haven't done the "math" on it (so can't be 100% sure).

Quote:gordonm888I've been playing the demo and I enjoyed playing this game. I'm not a big VP player, but I would look for this one.

1. Is this placed in live casinos (pandemic notwithstanding)? In internet casinos?

2. If I have 4 cards to a straight and only draw 1 card, is my chance of drawing a multidraw card lower than when I draw multiple cards?

Thank you, gordonm888.

As of right now, it is not in any casino. The virus got in the way and we are in a holding pattern, along with several of our other games, until it gets itself all figured out. Hopefully, sooner than later.

According to the math for this version of the game, each time you draw a new card, you will have a 25% chance of the MD card appearing in that card position. So technically, the fewer cards you hold, the higher chance of the MD card appearing somewhere in the hand.

Quote:gordonm888I've been playing the demo and I enjoyed playing this game. I'm not a big VP player, but I would look for this one.

1. Is this placed in live casinos (pandemic notwithstanding)? In internet casinos?

2. If I have 4 cards to a straight and only draw 1 card, is my chance of drawing a multidraw card lower than when I draw multiple cards?

Thank you, gordonm888.

As of right now, it is not in any casino. The virus got in the way and we are in a holding pattern, along with several of our other games, until it gets itself all figured out. Hopefully, sooner than later.

According to the math for this version of the game, each time you draw a new card, you will have a 25% chance of the MD card appearing in that card position. So technically, the fewer cards you hold, the higher chance of the MD card appearing somewhere in the hand.

Quote:ksdjdjI was just wondering because of the higher chance of getting the "MD", but is it better to keep two pairs or to keep just the high pair (if one of the pairs is "jacks or better")?

I would guess you would keep the "high pair only" in this situation, but I haven't done the "math" on it (so can't be 100% sure).

Great question ksdjdj. I can ask my math guy to see what he thinks. My method of playing would be to hold the two pair and take my chances of getting an MD card and getting one or more full houses. In the case of a pair of aces and another pair, I think I would just hold the aces.

https://www.facebook.com/groups/682004145971896/?ref=group_header

Quote:RealizeGamingI was playing around with some of our demos in order to get screenshots of decent wins and I was able to get a royal flush. Always nice to see those type of wins!

Demo: https://www.realizegamingllc.com/demo/mdDDB2/

I was playing around with the "Twin Twin Bonus (DDB)" and I have started a list of hands that are better ( may be better) to go for the "higher chance of getting the MD"

Note: The dollar values stated are the "$-RTPs" for a "DDB game with the same pay-table listed above" playing 5 x $1 ($5), and the values are rounded to the nearest $0.01.

Note 2: I haven't done the math of what the MD is worth in these scenarios , instead I have only put an "MD chance" figure there

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"4 to an inside straight (3 high)" vs "Jack - Queen (off-suit)" vs "an Ace"

Example: As, 5d, 10s, Jd, Qc

Keep "4 to a straight (3 high)" = $2.66 + "25% chance of an MD"

Keep "Jack - Queen (off-suit)" = $2.24 + "~58% chance of an MD"

Keep "an Ace" = $2.21 + "~68% chance of an MD"

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"Jack - King (off-suit)" vs "a Jack"

Example: 5c, Jh, Kd, 9c, 2d

Keep "Jack - King (off-suit)" = $2.25 + "~58% chance of an MD"

Keep "a Jack" = $2.16 + "~68% chance of an MD"

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"2 to a Royal Flush (1 high)" vs "a King"

Example: 10d, 5c, Qd, Ks, 6c

Keep "2 to a Royal Flush (1 high)" = $2.27 + "~58% chance of an MD"

Keep "a King" = $2.11 + "~68% chance of an MD"

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"2 Pair (with high pair)" vs "high pair"

Example: Kh, Kd, Ad, 10h, 10d

Keep "2 Pair (with high pair)" = $8.40 + "25% chance of an MD"

Keep "high pair" = $7.24 + "~58% chance of an MD"

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Conclusion: For the above hands, I would guess you should keep the cards that have the "highest chance of getting the MD", but I haven't done a "proper analysis" ? (I am only listing them so far)

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Quote:ksdjdjQuote:RealizeGamingI was playing around with some of our demos in order to get screenshots of decent wins and I was able to get a royal flush. Always nice to see those type of wins!

Demo: https://www.realizegamingllc.com/demo/mdDDB2/

I was playing around with the "Twin Twin Bonus (DDB)" and I have started a list of hands that are better ( may be better) to go for the "higher chance of getting the MD"

Note: The dollar values stated are the "$-RTPs" for a "DDB game with the same pay-table listed above" playing 5 x $1 ($5), and the values are rounded to the nearest $0.01.

Note 2: I haven't done the math of what the MD is worth in these scenarios , instead I have only put an "MD chance" figure there

---

"4 to an inside straight (3 high)" vs "Jack - Queen (off-suit)" vs "an Ace"

Example: As, 5d, 10s, Jd, Qc

Keep "4 to a straight (3 high)" = $2.66 + "25% chance of an MD"

Keep "Jack - Queen (off-suit)" = $2.24 + "~58% chance of an MD"

Keep "an Ace" = $2.21 + "~68% chance of an MD"

---

"Jack - King (off-suit)" vs "a Jack"

Example: 5c, Jh, Kd, 9c, 2d

Keep "Jack - King (off-suit)" = $2.25 + "~58% chance of an MD"

Keep "a Jack" = $2.16 + "~68% chance of an MD"

---

"2 to a Royal Flush (1 high)" vs "a King"

Example: 10d, 5c, Qd, Ks, 6c

Keep "2 to a Royal Flush (1 high)" = $2.27 + "~58% chance of an MD"

Keep "a King" = $2.11 + "~68% chance of an MD"

---

"2 Pair (with high pair)" vs "high pair"

Example: Kh, Kd, Ad, 10h, 10d

Keep "2 Pair (with high pair)" = $8.40 + "25% chance of an MD"

Keep "high pair" = $7.24 + "~58% chance of an MD"

---

Conclusion: For the above hands, I would guess you should keep the cards that have the "highest chance of getting the MD", but I haven't done a "proper analysis" ? (I am only listing them so far)

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Impressive analysis. Thanks for spending time to put that together.

Game: https://www.realizegamingllc.com/demo/mdDDB2/

Assumptions:

. You can't get an "MD" on the deal.

. You can get a maximum of one "MD" , per game.

. Chance of an "MD" = 25% per "drawn card" .

. Average number of cards drawn when you get an "MD" = 2.90

. Average value of each "MD" card (when drawn) = 1.504

."Expected Value"/Combined average value of the "MD", if you draw it = 4.3616 (2.9 x 1.504)

Scenario:

Is it better to "keep a dealt Full-house" vs "keeping the 3 of a kind and going for the "MD" on the draw " ?

Example: 5d, 5h, 5c, 10d, 10h

Answer: It is better to keep the 3 of a kind (3oK) and go for the "MD"...

"Proof":

Keeping a dealt full-house is worth: 45

Keeping just the 3 of a kind... is worth: 66.361... ***

*** (see working below):

For a "normal game of DDB" with this game's pay-table, a 3oK is worth 26.859... (so keeping the dealt full-house would obviously be the better play, when playing a "normal game")

But with this game, you can get an "MD" card on the draw.

So , the real value of keeping a 3oK in this game is:

("Chance of NOT getting an MD" x "base value of a 3oK") + ("Chance of getting an MD" x "Expected Value of the MD" x "base value of a 3oK") = "real value"

= ( (0.75^2) x 26.859... ) + ((1- ( 0.75^2)) x 4.3616 x 26.859...) = 15.108... + 51.253... = 66.361...

66.361 (3oK) is bigger than 45 (dealt full-house), therefore the better play is to keep the 3ok, for the above scenario.

Note: This is just to prove that a "3oK" is the better play for this game, if you want to work out the real "RTP" of each play, then divide these amounts by 15 (since the total cost for this game is $15 per game).

Note 2: This is just the "proof and working" for keeping a "normal 3oK".

Note 3: From this proof, you can infer that keeping a "special^^^ 3oK" is also the correct play, when you are dealt a full-house.

^^^:"Special 3oK"s are, a "3oK in Aces", and "3oK in twos, threes or fours".

----

Can someone check if the "MD" figures I used are correct, and also the general math...? (thanks)

It took me an hour or so just to work out and write this post, so hopefully someone better (more efficient?) can take it from here?

Spelling not checked thoroughly (if you are wondering why I often write something like this at the end of my posts, it is mainly because I have trouble concentrating, especially when I read/write long posts)

Quote:ksdjdjHere is a "deeper" analysis of a dealt full-house ("deeper" when compared to what I did in my previous post).

Game: https://www.realizegamingllc.com/demo/mdDDB2/

Assumptions:

. You can't get an "MD" on the deal.

. You can get a maximum of one "MD" , per game.

. Chance of an "MD" = 25% per "drawn card" .

. Average number of cards drawn when you get an "MD" = 2.90

. Average value of each "MD" card (when drawn) = 1.504

."Expected Value"/Combined average value of the "MD", if you draw it = 4.3616 (2.9 x 1.504)

Scenario:

Is it better to "keep a dealt Full-house" vs "keeping the 3 of a kind and going for the "MD" on the draw " ?

Example: 5d, 5h, 5c, 10d, 10h

Answer: It is better to keep the 3 of a kind (3oK) and go for the "MD"...

"Proof":

Keeping a dealt full-house is worth: 45

Keeping just the 3 of a kind... is worth: 66.361... ***

*** (see working below):

For a "normal game of DDB" with this game's pay-table, a 3oK is worth 26.859... (so keeping the dealt full-house would obviously be the better play, when playing a "normal game")

But with this game, you can get an "MD" card on the draw.

So , the real value of keeping a 3oK in this game is:

("Chance of NOT getting an MD" x "base value of a 3oK") + ("Chance of getting an MD" x "Expected Value of the MD" x "base value of a 3oK") = "real value"

= ( (0.75^2) x 26.859... ) + ((1- ( 0.75^2)) x 4.3616 x 26.859...) = 15.108... + 51.253... = 66.361...

66.361 (3oK) is bigger than 45 (dealt full-house), therefore the better play is to keep the 3ok, for the above scenario.

Note: This is just to prove that a "3oK" is the better play for this game, if you want to work out the real "RTP" of each play, then divide these amounts by 15 (since the total cost for this game is $15 per game).

Note 2: This is just the "proof and working" for keeping a "normal 3oK".

Note 3: From this proof, you can infer that keeping a "special^^^ 3oK" is also the correct play, when you are dealt a full-house.

^^^:"Special 3oK"s are, a "3oK in Aces", and "3oK in twos, threes or fours".

----

Can someone check if the "MD" figures I used are correct, and also the general math...? (thanks)

It took me an hour or so just to work out and write this post, so hopefully someone better (more efficient?) can take it from here?

Spelling not checked thoroughly (if you are wondering why I often write something like this at the end of my posts, it is mainly because I have trouble concentrating, especially when I read/write long posts)

Great information, ksdjdj.

I do agree with your belief that breaking up a full house by keeping the trips is the correct play. I also wonder how much that would change if there was still possibility of getting a MD on the draw of the game, even without any open card positions (similar to Double Super Times Pay). My guess is that it will get added to the game at some point to provide the opportunity for the MD card on dealt winning hands.

Quote:RealizeGamingGreat information, ksdjdj.

I do agree with your belief that breaking up a full house by keeping the trips is the correct play. I also wonder how much that would change if there was still possibility of getting a MD on the draw of the game, even without any open card positions (similar to Double Super Times Pay). My guess is that it will get added to the game at some point to provide the opportunity for the MD card on dealt winning hands.

I like the current way with no MD on pat hands and a variable overall probability of MD based on number of cards drawn. Creates the opportunity for mistakes which, theoretically, might result in the casinos allowing for a lower house edge for players who take the time to develop/learn optimal strategy.