January 16th, 2024 at 6:29:21 AM
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Hi there,
Was wondering how to calculate the seed/hold % of a mhb if you're aware of the rtp, the meter rate.
Was wondering how to calculate the seed/hold % of a mhb if you're aware of the rtp, the meter rate.
January 16th, 2024 at 9:21:20 AM
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https://wizardofvegas.com/forum/gambling/slots/18030-must-hit-by-progressives-for-dummies/#post354826
You might check this older discussion.
(There is a really good writeup here, somewhere, but I can't find it just now. (Mission?))
You might check this older discussion.
(There is a really good writeup here, somewhere, but I can't find it just now. (Mission?))
May the cards fall in your favor.
January 16th, 2024 at 9:25:55 AM
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Example 90% rtp
100$ moves meter 1$ on the minor
What other information is needed to figure out how much of the rtp is held in the progressive?
100$ moves meter 1$ on the minor
What other information is needed to figure out how much of the rtp is held in the progressive?
January 16th, 2024 at 11:09:15 AM
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Quote: WestduckHi there,
Was wondering how to calculate the seed/hold % of a mhb if you're aware of the rtp, the meter rate.
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Let s = the seed, which is the starting amount of the progressive.
Let m = the must-hit-by amount.
Let r = the meter rate, which is the rise of the progressive divided by the coin-in.
I find that the meter's contribution to the slot's return-to-play (RTP) is: r.
And the seed's contribution to the slot's RTP is: 2 * r * s / (m - s).
[Or you can combine the meter's and seed's contributions to get: r * (m + s) / (m - s).]
January 16th, 2024 at 11:45:34 AM
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When you say "rise of the progressive"
Do you mean the latest it can hit subtracted by the starting point?
Do you mean the latest it can hit subtracted by the starting point?
January 16th, 2024 at 3:38:25 PM
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Quote: WestduckWhen you say "rise of the progressive"
Do you mean the latest it can hit subtracted by the starting point?
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No, but you can disregard that part of the sentence.
I should have typed:
Let s = the seed, which is the starting amount of the progressive.
Let m = the must-hit-by amount.
Let r = the meter rate.
(For those who don't know what "meter rate" is, it's the number of dollars the progressive went up divided by the number of dollars played. For example, if the progressive went up by $0.01 after I played $1.00, the meter rate would be $0.01 / $1.00 = 0.01 = 1%.)
January 18th, 2024 at 9:07:41 PM
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Perfect.
One more thing.. how to account for the minor if you're playing solely for the minor
One more thing.. how to account for the minor if you're playing solely for the minor
January 18th, 2024 at 10:18:42 PM
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Quote: WestduckPerfect.
One more thing.. how to account for the minor if you're playing solely for the minor
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For a machine with only two progressives, call the minor "1" and the major "2." The contributions of the seeds and the meters to the RTP would be:
r1 * (m1 + s1) / (m1 - s1) + r2 * (m2 + s2) / (m2 - s2)
Ignoring the minor and major, you would expect to lose this fraction (F) of money bet:
F = 1 - RTP + r1*(m1+s1)/(m1-s1) + r2*(m2+s2)/(m2-s2)
The minor would be expected to hit at (N1 + m1) / 2, where N1 means the size of the minor now.
The expected amount of money you would have to bet to hit the minor would be:
[(N1 + m1) / 2 - N1] / r1 = (m1 - N1) / (2 * r1)
Ignoring the major, set the expected amount of money lost along the way to what the minor would pay, and solve for the break-even value of the minor N1:
F * (m1 - N1) / (2 * r1) = (N1 + m1) / 2
Ignoring the major, the minor would have to be at least this amount to break even:
N1 = m1 * (F - r1) / (F + r1)
January 23rd, 2024 at 8:55:46 AM
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Thank you very much
January 23rd, 2024 at 9:10:29 AM
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r1 * (m1 + s1) / (m1 - s1) + r2 * (m2 + s2) / (m2 - s2)
After using this formula, I get a hold of .042
In your experience, could this be right for an ainsworth? Or is it too high and I mightve miscalculated?
After using this formula, I get a hold of .042
In your experience, could this be right for an ainsworth? Or is it too high and I mightve miscalculated?
January 23rd, 2024 at 9:41:53 AM
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Quote: Westduckr1 * (m1 + s1) / (m1 - s1) + r2 * (m2 + s2) / (m2 - s2)
After using this formula, I get a hold of .042
In your experience, could this be right for an ainsworth? Or is it too high and I mightve miscalculated?
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Below are some data from the Wizard's page on Ainsworth must-hit-bys.
JACKPOT | MINOR | MAJOR |
---|---|---|
Starting point | $20 | $350 |
Must hit by | $50 | $400 |
Rate of increase (based on bet) | 0.45% | 0.20% |
Using the above data, I get r1 * (m1 + s1) / (m1 - s1) + r2 * (m2 + s2) / (m2 - s2) = 0.0105 + 0.0300 = 0.0405 = 4.05%.
So, your 0.042 is comparable to the Wizard's example.
I don't check must-hit-bys, so I don't have any data of my own to compare.