January 14th, 2016 at 7:14:51 AM
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Suppose on a 5c machine I have hit a particular prize (somewhat like a jackpot) 13 times after 1000 spins.

Suppose on a 2c machine I have hit it 5 times after 1000 spins.

How confident can I say the two machines have different settings for the particular prize?

Suppose on a 2c machine I have hit it 5 times after 1000 spins.

How confident can I say the two machines have different settings for the particular prize?

Last edited by: supergrass on Jan 14, 2016

January 14th, 2016 at 7:52:08 AM
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Simple answer: 0

Playing it correctly means you've already won.

January 17th, 2016 at 8:33:43 PM
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assuming the probability of a jackpot is 1%, the standard deviation is for 1000 spins is 3.6, so that means that the 5c machine is less than 1 standard deviation over and the 2c machine would be 1.5 standard deviation under, both are within statistically accepted ranges.

with such a small sample size its not possible to detect with confidence that the machines are on different settings

variance of a set of spins = npq

n=number of spins

p=probability of jackpot

q=probability of non-jackpot

with such a small sample size its not possible to detect with confidence that the machines are on different settings

variance of a set of spins = npq

n=number of spins

p=probability of jackpot

q=probability of non-jackpot

January 19th, 2016 at 9:49:48 AM
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If I knew the 5c machine jackpot chance is 1.3% and the 2c machine only hit 5 times then I can say the 2c machine is different with over 98.5% confidence. Calculation:

1000 spins, mean is 13 hits, result is 5 times, so 8 times less than expectation.

The standard deviation is 3.6 hits, so 2.22 SD below expectation.

So only 1.5% chance it happened due to bad luck.

It seems to me even with 5 hits, the sample size is big enough to get over 95% confidence interval.

However the difficulty is I don't know the true 5c jackpot chance. I only know based on my sample test the chance is 1.3%.

1000 spins, mean is 13 hits, result is 5 times, so 8 times less than expectation.

The standard deviation is 3.6 hits, so 2.22 SD below expectation.

So only 1.5% chance it happened due to bad luck.

It seems to me even with 5 hits, the sample size is big enough to get over 95% confidence interval.

However the difficulty is I don't know the true 5c jackpot chance. I only know based on my sample test the chance is 1.3%.

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