which bet would you make and why???
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Quote: spadeknightIf i owned a casino and offered you a chance to bet 500 dollars all at once on either blackjack or roulette which bet would you make???
Correct me if I'm wrong, but doesn't every casino in the world offer this opportunity? Or do you mean I get to bet THEIR money?
If I were allowed to split up the bet, I'd put $236 on black, $236 on red, and $14 on each zero. If not, I'd probably put it all on Odd or Even. I wouldn't play blackjack, even though the house edge is lower, because I might have to double down or split.
Of course, the real question is: Why is this in the Craps forum?
$500 of my own and I'll be playing Blackjack, slowly.
BJ. Be happy to double because you have +EV. You can avoid splitting, if the split was -EV if its a +EV split be happy.Quote: spadeknightsorry about asking a question about roulette or blackjack in a craps forum but as a craps player i want to know how my craps friends would play other table games under certain circumstances. The 500 is of course the casinos money so you arent risking anything. however you do get a chance to find the best way to win against two popular games. by getting input about other peoples strategies i can decide which game i would decide to play in that situation.
Desert Inn was the first place to send me a $500 free chip bet, good until you lose. Played BJ.
Never touched a BJ game in the place before that. They had 9/6 $5 VP 1% card and other things.
If me... 80 force with 400 Odds
Roulette... European: 250 Noir, 250 Impair
American... no f'in way.
Blackjack 6d S17 DAS RS4 RSA LS $200 and hope for DD and or 1-split.
VP: JoB 99.54% $100x5coin
PGP: $500 one time
Baccarat: $500 Player
Quote: RSThe proper play is to bet $13 ($500/38) on each number, straight up, on roulette. It is the most +EV, assuming you get only one shot and are using someone else's money.
No matter how you arrange your bets at roulette, the EV will be the same, as long as you avoid that five-number bet which I think is called the "basket."
I thought I said that?Quote: NowTheSerpentThere you go, Buzzard, insulting hats yet again. LOL!
Quote: EaglesnestNo matter how you arrange your bets at roulette, the EV will be the same, as long as you avoid that five-number bet which I think is called the "basket."
Not quite true.
Say you have $38. If you had one shot and bet every number straight up, you'd get paid $35 when a number hit and you'd lose the original wager (ie: one shot). If you bet each of the numbers $2 at a time on the in-between-line (ie: $2 on 0/00 split), you'd get paid $34 and lose the original wager.
If you do get to keep the chips, then playing the lowest HE game would probably be best.
If the 0 or 00 comes up, you would only lose half you bet ($125) on the Black and ($125) on the Red.
You are guaranteed to walk away with $250 no matter what number comes up
1) Lowest House Edge for Maximum Value: Blackjack, hands down. Lowest house edge (~.5%) you can find with basic strategy. I'd be prepared to put my own money up on the small chance you get a split/double situation. They generally only give you promotional chips in accordance to your level of play. Thus, a $500 chip you should easily be able to match $500 "if needed." The majority of the time BS will suffice for this bet.
2) Highest guaranteed amount back - Roulette $13 per number straight up including the zero's. This will return $455.
3) If you're not allowed to break it up like that, I'd probably go Don't Pass in craps, which would return the full $500 but at a 1.36% HE. Or if you really wanted 'guaranteed' money you could match your $500 with $500 and play the Pass & Don't Pass.
I think in the situation you're referring to we're assuming a $500 promo chip that CAN'T be broken down and you get to keep the winnings. In this case I'd back count a blackjack shoe and throw it in on the highest true count I could find =P. If that wasn't an option, I'd probably still play blackjack, baccarat, or craps, in that order.
Quote: NowTheSerpentYou would win $35 and lose $37, so the HE = -2/38 = -1/19 = -5.26% as usual. If you bet $2 across 0/00, only one can hit for $35, the other would lose. In 38 results, you'd lose $2 36 times and win $34 twice, so your return would be ($34*2 - $2*36)/($2*38) = -4/76 = -1/19 = -5.26% once again.
You're using someone else's money....
Quote: NowTheSerpentQuote: RSQuote: NowTheSerpentYou would win $35 and lose $37, so the HE = -2/38 = -1/19 = -5.26% as usual. If you bet $2 across 0/00, only one can hit for $35, the other would lose. In 38 results, you'd lose $2 36 times and win $34 twice, so your return would be ($34*2 - $2*36)/($2*38) = -4/76 = -1/19 = -5.26% once again.
You're using someone else's money....
OK. Their EV = -5.26%, but then I couldn't care less about someone else's money.
Re-read the OP. You should care about someone else's money. It can be the difference in getting 92% of the free bet money or just like 50%.
And the casino's EV is about -92%. Are you not reading what I've been writing?
Quote: RSNot quite true.
Say you have $38. If you had one shot and bet every number straight up, you'd get paid $35 when a number hit and you'd lose the original wager (ie: one shot). If you bet each of the numbers $2 at a time on the in-between-line (ie: $2 on 0/00 split), you'd get paid $34 and lose the original wager.
If you do get to keep the chips, then playing the lowest HE game would probably be best.
I didn't say the result would always be the same; I said the EV would always be the same. This simple truth is why no betting system used in a negative EV game will ever produce a positive outcome: all you can do is rearrange the negative results.
Quote: EaglesnestI didn't say the result would always be the same; I said the EV would always be the same. This simple truth is why no betting system used in a negative EV game will ever produce a positive outcome: all you can do is rearrange the negative results.
If you're using your own money, the EV is the same. But if the money is being treated as "free bet" money, then no, the EV is not the same.
Anyway, free bets that are taken on a win, the HE is not the most important factor. Actually, it's not really even a factor. I'll try this one more time:
If you bet on BLACK, you get 18 ways to win 1 unit and 20 ways to lose (or rather, nothing happens since it's not actually your money). If you bet 0 straight up, you have 1 chance to win 35 units, and 37 ways for nothing to happen (you lose it).
On even money bets, the return is 18/38. For betting straight up, the return is 35/38. There's clearly a difference.
Are you getting a 35/38 return on your free bet BJ wagers?
