charliepatrick
charliepatrick
Joined: Jun 17, 2011
  • Threads: 34
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Thanks for this post from:
teliotunJon
September 15th, 2021 at 3:04:13 AM permalink
An easier solution (which loses more) is
4x 3 2 < A K
4x Q 8 < J 9
4x 6 5 (double) 4 < 7 T (7 is dealer's up-card, so correct to double 11)

I don't know but this gives the 20 units profit for the player in a single deck
4x A K > 2 3 (wins 1.5 units each)
4x 7 4 (Q) > 8 J (doubled 11 vs 8, so wins 2 units each)
1x 5 6 (9) > 9 T (doubled 11 vs 9)
1x 5 6 (T) > 9 T (doubled 11 vs 9)
1x 5 6 (T) > 9 5 6 (doubled 11 vs 9)
Total win = 6+8+6 = 20


four split (and doubled) hands of 8 3 (Q) > 7 T
four split (and doubled) hands of 9 2 (K) > 7 T
four split (and doubled) hands of 6 A (5) > 4 T T
This leaves JJJJ77444 to create
two split (and doubled) hands of 7 4 (J) > 4 J J
I suspect you can use similar ideas to have the player lose more in a single shoe!
unJon
unJon
Joined: Jul 1, 2018
  • Threads: 14
  • Posts: 2864
September 15th, 2021 at 4:36:40 AM permalink
Quote: charliepatrick

An easier solution (which loses more) is
4x 3 2 < A K
4x Q 8 < J 9
4x 6 5 (double) 4 < 7 T (7 is dealer's up-card, so correct to double 11)

I don't know but this gives the 20 units profit for the player in a single deck
4x A K > 2 3 (wins 1.5 units each)
4x 7 4 (Q) > 8 J (doubled 11 vs 8, so wins 2 units each)
1x 5 6 (9) > 9 T (doubled 11 vs 9)
1x 5 6 (T) > 9 T (doubled 11 vs 9)
1x 5 6 (T) > 9 5 6 (doubled 11 vs 9)
Total win = 6+8+6 = 20


four split (and doubled) hands of 8 3 (Q) > 7 T
four split (and doubled) hands of 9 2 (K) > 7 T
four split (and doubled) hands of 6 A (5) > 4 T T
This leaves JJJJ77444 to create
two split (and doubled) hands of 7 4 (J) > 4 J J
I suspect you can use similar ideas to have the player lose more in a single shoe!
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    This is great. Thank you.
    The race is not always to the swift, nor the battle to the strong; but that is the way to bet.
    ThatDonGuy
    ThatDonGuy 
    Joined: Jun 22, 2011
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    Thanks for this post from:
    Dieter
    September 15th, 2021 at 12:17:28 PM permalink
    Quote: TomG

    I'm having trouble understanding this. Are there really streaks that may or may not happen after an infinite amount of hands? If a streak "can" happen, but has not yet happened, shouldn't that mean there was not an infinite amount of hands played.

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    The numbers 1, 2, 3, ... are an infinite set of numbers. Let each number represent a hand.
    Choose any positive integer N.
    Regardless of what number N is, it is possible to lose hand number N.
    FinsRule
    FinsRule
    Joined: Dec 23, 2009
    • Threads: 121
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    September 15th, 2021 at 9:49:21 PM permalink
    I think I dislike arguments about infinity more than I dislike betting system arguments.

    I wish we could ban them on this forum.
    billryan
    billryan
    Joined: Nov 2, 2009
    • Threads: 192
    • Posts: 11746
    September 17th, 2021 at 1:54:04 PM permalink
    Quote: FinsRule

    I think I dislike arguments about infinity more than I dislike betting system arguments.

    I wish we could ban them on this forum.

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    You are just jealous because you don't have an infinite bankroll. Were you to have one, you might look at the discussions with a different view.

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