Joined: Apr 20, 2020
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April 20th, 2020 at 12:12:32 AM permalink
I wanted the input from the more knowledgeable AP's about the concept of "inverse spreading" also known as "Grifter Gambit."

The theory is (when playing HEADS UP) instead of betting 1 unit at TC < 1, we bet 3 hands of .33 units at TC < 1. This accomplishes a higher expectation PER ROUND, because we metaphorically eat through the bad counts to get to the good counts quicker. Also, the concept is we move our max bet out to 1 hand of x units as to get more rounds in +EV situations.

RESULTS: Higher Win-rate, lower ROR bankroll restrictions, camouflage. (according to zengrifter)

Normal High-Low​ Inverse hand spreading​ difference​ 6d, S17, DAS, 3/4 PEN, 8-1 spread max bet at TC>3=8u (TOP)

TC>=1, TC<2= 2x2u
TC>=2, TC<3= 2x3u
TC>=3 = 1x24u


Std. dev./round

Avg. bet size.

Win rate/hour

5% ROR 8 hour trip bankroll

5% lifetime ROR bankroll

Does this look correct? I know the original spread is sub-optimal and you math wizards can find your optimal betting spread, I just wanted to introduce this concept for those who didn't know of it and to get comments on its validity.
Joined: Aug 8, 2010
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April 20th, 2020 at 6:17:21 AM permalink
Maybe just semantics, but if you are at a $15 table, say, What are you calling a unit? If my lowest bet will be $15, that's what I call a unit. It seems like you are just starting at 3 units, or $45. And going down to 1 unit when doing your spreading to 3 hands play. So if you bet $450, which is ten times your ORIGINAL wager, you, in my mind are not spreading 1-10, but rather, actually spreading 1-30. If you can get away with that, great.
Joined: Jan 5, 2013
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April 20th, 2020 at 8:49:13 AM permalink
Try it after Covid-19 and let us know if you survive spreading 3x$25 to 1x$600
G Man
Joined: Jun 17, 2011
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April 20th, 2020 at 9:50:05 AM permalink
I'm guessing the question is whether it's better to play one hand at $15 or three hands at $5.

Assuming it's -EV then playing 1-1 gets rid of more cards. Suppose the average for simplicity was 3 cards each, then playing 1-1 you would get rid of 6 cards per round (Player + Dealer) and it costs you the -EV of one bet. Playing 3-1 (Player*3 + Dealer) gets rid of 12 cards for the cost of three bets.

If your bets were $15 or 3 x $5 it's best to have 3 x $5 since you get rid of 12 cards. However if you could bet $5, you would be better off playing 1-1 at $5. Not only because it costs less to get rid of cards but also if it turned positive you can then increase your bet earlier.

The only reason I can see you wanting to bet $15 in total is to establish that as your base total bet, so allowing you a larger bet when it turns good.

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