Riptide
Riptide
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Joined: Jan 24, 2013
January 24th, 2013 at 11:43:13 PM permalink
It's my first post here. Apologies in advance if this question has been answered previously. I tried the search function but couldn't lock-on to a post.

Anyway, I am running into trouble calculating the expected values for standing when the dealer is showing a 10. When I calculate the expected value, I am slightly off when compared to Appendix 9.

Assuming a single deck and the dealer stands on soft 17, a hand of 10,6 vs. 10 should have an EV = -.542952. I calculate is EV=-.5803. The algorithm I wrote works fine for upcards 2-9.

The general equation I'm using is EV = 2[P(T > 21) + P(T < j)] + P(T = j) - 1 where T are all possible dealer hands 17-21+ (including busts) and j is the value of the player hand. Does it have something to do with the fact that we know the dealer's second card will not be an ace, we calculate the probabilities slightly differently?
1BB
1BB
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Joined: Oct 10, 2011
January 25th, 2013 at 4:03:16 AM permalink
A post on Blackjackinfo has it at - 0.580261906574.
Many people, especially ignorant people, want to punish you for speaking the truth. - Mahatma Ghandi
dwheatley
dwheatley
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January 25th, 2013 at 5:00:04 AM permalink
Quote: Riptide

Does it have something to do with the fact that we know the dealer's second card will not be an ace, we calculate the probabilities slightly differently?



Yes, yes, very much yes.
Wisdom is the quality that keeps you out of situations where you would otherwise need it
CrystalMath
CrystalMath
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Joined: May 10, 2011
January 25th, 2013 at 8:14:27 AM permalink
Quote: Riptide

It's my first post here. Apologies in advance if this question has been answered previously. I tried the search function but couldn't lock-on to a post.

Anyway, I am running into trouble calculating the expected values for standing when the dealer is showing a 10. When I calculate the expected value, I am slightly off when compared to Appendix 9.

Assuming a single deck and the dealer stands on soft 17, a hand of 10,6 vs. 10 should have an EV = -.542952. I calculate is EV=-.5803. The algorithm I wrote works fine for upcards 2-9.

The general equation I'm using is EV = 2[P(T > 21) + P(T < j)] + P(T = j) - 1 where T are all possible dealer hands 17-21+ (including busts) and j is the value of the player hand. Does it have something to do with the fact that we know the dealer's second card will not be an ace, we calculate the probabilities slightly differently?



I spent about 30 minutes trying to figure out where everyone went wrong, until I realized that you are calculating the ev of STANDING on 10,6 vs 10.

If the dealer hasn't checked for blackjack yet, the ev is -0.580261907, which matches Blackjackinfo.
If the dealer has checked for blackjack, and you know that the dealer doesn't have a blackjack, the ev is -0.542951854, which matches Appendix 9.

But, the player should hit, so the ev is as follows:
Dealer hasn't checked for blackjack: ev = -0.5471799166540101
Dealer checked and doesn't have blackjack: ev = -0.5071033260810114

Should surrender be available, ev = -0.5, which is the best option.
I heart Crystal Math.
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