NowTheSerpent
NowTheSerpent
Joined: Sep 30, 2011
  • Threads: 15
  • Posts: 417
November 3rd, 2011 at 8:10:43 AM permalink
Quote: MrCasinoGames

I don't think a new dice game can make it to the Casino.



How about Hard Luck?

Two players: dealer (designated dice thrower) and banker, two dice each. Object: throw a higher sum than opponent. Win pays even money.

Tie-sums (146 in all) happen three ways:

(1) hard-hard (all four dice same, a quadruple) = pay even money to both Dealer and Banker bets (6 ways)

(2) easy-easy, same combo (two-pair X&Y) = take half from both (60 ways)

(3) easy-easy, diff. combo (one-pair X&Y=S, one pair W&Z=S) = higher-order combo wins (80 ways in all, 40 behooving each).

Definition: higher order = having smaller difference between numbers on each die. For example: 3&3 beats 2&4 and 1&5, 2&4 beats 1&5. Thus, hardways would be a special case included in the rule. Very simple to use, actually.

House edge on the above description = 1.85%

Side bets

(1) Spread - difference between dice sums - pays on a scale as follows (for HA = 11.73% / for HA = 2.78%)

10-Spread (maximum, 2 possible ways) 80 to 1 / 84 to 1
9-Spread (8 ways) 20 to 1 / 21 to 1
8-Spread (20 ways) 8 to 1 / 42 to 5
7-Spread (40 ways) 4 to 1 / 21 to 5
6-Spread (70 ways) 2 to 1 / 12 to 5
5-Spread (minimum, 112 ways) 1 to 1 / 3 to 2

(2) Chance - four-die outcome, regardless of which dice are whose

Any Triple (X&X&X&Y, 120 ways) - pays 2 to 1
Any Two-Pair (X&X&Y&Y, 90 ways) - pays 3 to 1
Any Straight (1&2&3&4, 2&3&4&5, or 3&4&5&6, 72 ways in all) - pays 4 to 1
Any Quadruple (X&X&X&X, 6 ways, obviously) - pays 23 to 1 (HA = 5.56%) or 29 to 1 (HA = 2.78%)

(3) Above- or Below-14: four-die total of greater than or less than 14, each pays even money (HA = 11.27%) or 6 to 5 (HA = 2.39%)

Dealer chooses which dice to be his own and throws both his own and the banker's dice (to keep the appearance of absolute honesty). Keeps dice as long as the Dealer bets continue to win (Like-combo tie with banker counts as a loss).

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