September 12th, 2015 at 2:42:47 PM
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Quote: slackyhackyI don't understand your math - I mean what each number is suppose to represent.
However, use English - or explain to me like I am 10 years old...
If I risk three dollars, and win four dollars - I make 133% of my original bet.
If I risk five dollars, and win seven dollars - I make 140% of my original bet.
How is that not worse to bet $3 to win $4?
$5 5: Win $7 40% of the time and lose $5 60% of the time. On a average you will lose 20 cents per resolved bet.
$3 5: Win $4 40% of the time and lose $3 60% of the time. On a average you will lose 20 cents per resolved bet.
“Man Babes” #AxelFabulous
September 12th, 2015 at 4:04:41 PM
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Thanks!
September 12th, 2015 at 9:49:56 PM
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MathExtremist and miblet - I now get what you are saying...
And for the casino, the amount of money per hour they are making is the same.
But...I'm still struggling...(I probably drove teachers crazy)
I know the 3$ casino's don't do this - but lets say they keep with the 1 unit integer.
So let's say I press this unit 5 times - now showing $15. Payout would be (keeping with the same math) $20 (15/3 = 5 - and payout is $4 per unit - so 4x5 = $20).
But on a "regular" table, payout on $15 dollars (3 units) is $21 dollars.
Using your math above, the table that stays with the $3 units expects to win $1/ hour for place bets on the 5 with five $3 dollar units (0.20 x 5), and on regular table, this is only 0.60.
I still don't see how they are the same.
BUT - I do get that casino's don't do this - that is, after $3, they seem to move to $5 dollar intervals - although I never tried placing $6 or $9 on the 5.
And for the casino, the amount of money per hour they are making is the same.
But...I'm still struggling...(I probably drove teachers crazy)
I know the 3$ casino's don't do this - but lets say they keep with the 1 unit integer.
So let's say I press this unit 5 times - now showing $15. Payout would be (keeping with the same math) $20 (15/3 = 5 - and payout is $4 per unit - so 4x5 = $20).
But on a "regular" table, payout on $15 dollars (3 units) is $21 dollars.
Using your math above, the table that stays with the $3 units expects to win $1/ hour for place bets on the 5 with five $3 dollar units (0.20 x 5), and on regular table, this is only 0.60.
I still don't see how they are the same.
BUT - I do get that casino's don't do this - that is, after $3, they seem to move to $5 dollar intervals - although I never tried placing $6 or $9 on the 5.
September 12th, 2015 at 11:53:22 PM
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$3 place 5 should pay $4.20 but there's breakage. Except every five units there isn't so the pay is correct, 5×3 pays 5×4.20 = 21.
"In my own case, when it seemed to me after a long illness that death was close at hand, I found no little solace in playing constantly at dice."
-- Girolamo Cardano, 1563
September 13th, 2015 at 10:11:18 AM
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Quote: MathExtremist$3 place 5 should pay $4.20 but there's breakage. Except every five units there isn't so the pay is correct, 5×3 pays 5×4.20 = 21.
Thanks. This point makes my point I think.
September 14th, 2015 at 8:10:52 PM
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A $3 PB on 4,5,9,&10 was a convenience bet available at the 25 cent games back in the day. $2.50 of the bet is normal 5X place bet payoff, while an additional 50 cents is "flat". Hence the increased HA.