## Poll

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**22 members have voted**

Quote:gordonm888First, if the players all bust then usually the dealer does not hit his hand to determine whether hhands of <17 would ahve gone bust. - do you lose the Buster BJ side-bet in this situation? Or does the dealer hits his cards anyway if he has less than a 17 in order to determine the outcome of the sidebet? If the dealer does not always play out his hand, the House Edge on the sidebet should be calculated assuming that the dealer does not play the hand when all players go bust -and thus the calculated side-bet should be a function of the number of players at the table.

I am very confused by this site:

The House edge is quoted to be different than what the Wizard just calculated for what appears to be the same assumptions on BJ rules. In this site's quoted simulation of 100M hands on a six-deck game with a card count of the A,2,3 cards, I don't understand if the dealer is assumed to play out his <17 hands when the player goes bust.

Differant pay table. I'm on my phone right now, but I did http://miplet.net/blackjack/busterblackjack.xlsb a while ago. Should be able to edit pay table and deck composition. I assume the dealer always plays out his hand.

Just having a quick look at your sheet. Call me naive but can you explain the titles H, D, S, C above the table on the left hand side. I can make a guess but just want to be sure. Thank you in advance!

Quote:WizardI saw a new pay table for Buster Blackjack and added it to my page. This one pays premium wins if the player has a blackjack and the dealer busts with seven or more cards.

So AGS added 6 units to the 6 Card Bust payout and an 800-1 & 2000-1 pay event and the HE only moved down 0.000116?

WOO, may I suggest you analyze Zombie Blackjack.Quote:WizardThanks. To be honest, I'm starting to run low on ideas.

first i think use number of combination is not reasonable.

then i think about number of permutation, when calculate the probabilty of buster with 3 cards,

B3=permutation of (sum of 3 cards>21 and sum of first 2 cards <17)

All=permutation of all 3 cards dealt

then the probabilty= B3/All

is my calculate right?