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Extra Draw Keno
| January 12th, 2012 at 2:07:53 AM permalink | |
| anorakgirl Member since: Jan 12, 2012 Threads: 1 Posts: 2 | Hi, Can anyone explain the Maths for Extra Draw Keno on this page: http://wizardofodds.com/games/keno/appendix/10/ I can work out the basic return for 20 balls out of 80, using the equation (x:y)*(80-x:20-y)/(80:20) But I can't work out the return from the extra 3 balls. I tried using the above equation with 60 and 3 instead of 80 and 20, working out the probability of getting 1, 2 or 3 extra balls and multiplying by the right payout, but it doesn't match the Wizards figures. I also divided the extra return by 2 due to the extra stake. Thanks for any help! |
| January 12th, 2012 at 8:52:52 AM permalink | |||||||||||
| CrystalMath Member since: May 10, 2011 Threads: 3 Posts: 476 | Let's just look at the simplest case: 3 spot 1. Using the formula stated above, these are the probabilities of hitting n spots:
2. After the first 20 draws, you have 60 open spots on the board and you have 3 draws (should you choose to do so). The wizard's table only shows that continuing is a good deal if you already hit 2 spots. So, this is the only one I will look at. There are only possible outcomes: you don't get the third spot or you do hit the third spot. The probability of hitting the additional spot is (x:y)*(60-x:3-y)/(60:3), where x and y are both 1 (p=0.05). 3. Calculate the return: r = p(hitting 2 spots in original 20 draws) * [p(hitting 1 additional spot in the next 3 draws) * increase in win - cost of additional wager] r = 0.138753651 * [0.05 * (30-3) - 1] = 0.048563778 I heart Crystal Math. | ||||||||||
| January 16th, 2012 at 12:50:12 AM permalink | |
| anorakgirl Member since: Jan 12, 2012 Threads: 1 Posts: 2 | Sorry I've only just had chance to come back to this - thanks for the explanation! |
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