Poll

5 votes (35.71%)
3 votes (21.42%)
1 vote (7.14%)
No votes (0%)
4 votes (28.57%)
1 vote (7.14%)
2 votes (14.28%)
1 vote (7.14%)
1 vote (7.14%)
4 votes (28.57%)

14 members have voted

BobDancer
BobDancer
Joined: Jun 22, 2013
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Thanks for this post from:
RogerKint
June 15th, 2017 at 10:38:40 PM permalink
I find I'm partial to solutions where Bob ends up getting the most!
billryan
billryan
Joined: Nov 2, 2009
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June 15th, 2017 at 11:47:27 PM permalink
God bless cowboys, God bless gold.
God bless my uncle, God rest his soul.
He taught me well, boys, taught me all I know.
Taught me so well that I grabbed the gold
Left his dead ass there by the side of the road
It's what you do and not what you say If you're not part of the future then get out of the way
darkoz
darkoz
Joined: Dec 22, 2009
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June 16th, 2017 at 4:13:43 AM permalink
Well here is the average man (non mathematician) answer

Bob and Jim were just being kind to the stranger. The payment was unexpected. Neither man being mathematically inclined or giving a damn about proportional consumption much less fractional computational math kept any track of who ate what

Happy they received coins from the stranger they split the money in either of two ways dependent on how much the bread originally cost

A) if the bread was an easily seen price e.g. $1 per loaf then Bob took $5 since he paid that for the bread while Jim takes $3 making this a free meal for both men ie returning them to being whole financially

B) if the bread was some weird amount e.g.$2.67 per loaf the 8 coins were split equally because neither Bob nor Jim hav the time nor interest(read intelligence) to do anything different

Anyway those are the real world answers :)
michael99000
michael99000
Joined: Jul 10, 2010
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June 16th, 2017 at 4:30:04 AM permalink
It is not stated in the question how much each man ate, so I'd make the following assumptions:

1) bob ate the most because he brought the most

2) Jim ate more than the stranger because Jim brought something and the stranger was just getting a free meal

3) each man ate a whole number loaves of bread

4) all 8 loaves the bread were consumed

The only solution that satisfies all four of those is Bob ate 4, Jim ate 3, stranger ate 1

So it turns out that Jim ate exactly what he brought to the dinner , bob ate four of the five loaves he brought and the stranger ate one of the loaves bob brought. Therefore bob should get all 8 coins.
prozema
prozema
Joined: Oct 24, 2016
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June 16th, 2017 at 4:33:34 AM permalink
If the bread (slot) machine malfunctioned, a 4th dude would use that as an excuse to take all the coins. (Malfunction voids all pays)
Joeman
Joeman
Joined: Feb 21, 2014
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June 16th, 2017 at 4:48:36 AM permalink
Quote: Wizard

Yes, this is the answer I was looking for. Congratulations!

If only you had posed this question back in April, I would have been able to collect! As it is, there is currently no Vegas trip on my horizon. I will gladly donate my beer to whichever local WoV member is the thirstiest.
"Dealer has 'rock'... Pay 'paper!'"
Wizard
Administrator
Wizard
Joined: Oct 14, 2009
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June 16th, 2017 at 7:28:11 AM permalink
Quote: michael99000

It is not stated in the question how much each man ate, so I'd make the following assumptions:



Absent information to the contrary, I think it is reasonable to assume they each ate the same amount of bread.
It's not whether you win or lose; it's whether or not you had a good bet.
boymimbo
boymimbo
Joined: Nov 12, 2009
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June 16th, 2017 at 8:01:34 AM permalink
If one person brings 5 loaves and another person brings 3, either the two have an agreement ipso facto that:

The 8 loaves are community bread and we can eat up to four each -or-
5 of these loaves belong to you, 3 belong to me. I get to eat 3 loaves, you get to eat 5.

There are variations of course: they're different kinds of bread, one bread is more expensive. None of these are stated.

The payment of the 8 coins should be based on the ipso facto arrangement.

If it is the first arrangement, payment is equal (they are one happy commune)
If it is the 2nd arrangement, 5 goes to the person who brought 5 and 3 to the person who brought 3.
----- You want the truth! You can't handle the truth!
TigerWu
TigerWu
Joined: May 23, 2016
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June 16th, 2017 at 8:10:41 AM permalink
Quote: darkoz



A) if the bread was an easily seen price e.g. $1 per loaf then Bob took $5 since he paid that for the bread while Jim takes $3 making this a free meal for both men ie returning them to being whole financially



That is exactly my reasoning and what I think is the "real-world-non-mathematician" answer.

It is completely irrelevant who ate how much bread. Bob is in the red financially for the cost of 5 loaves of bread, and Jim is in the red for the proportionate amount for 3 loaves of bread. They should split the coins proportionate to the amount of bread they each brought, not by how much was eaten.
darkoz
darkoz
Joined: Dec 22, 2009
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June 16th, 2017 at 9:22:06 AM permalink
Here is another similar question

A math Wizard and an AP meet for dinner. They agree to split the check

After the check is served the math Wizard says his share of the bill is 1/7 because he ate less food than the AP. He uses a calculator to prove it. The AP says they both should pay equally because they agreed to split the bill

The waitress overhears the argument and suggests they each pay for the cost of their respective orders to settle the argument

Both the Wizard and the AP demand the casino host be contacted so he can pay for the meal as a comp

The casino host agrees to pay for the entire meal if both players gamble over $1000

The Wizard and the AP play the doey dont at Craps

They agree to split the cost of the losses

How much money does the Wizard and the AP split?

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