Probability question.

If there are 6 tickets and 5 of them have your name on it, what are the chances to that your name will not be drawn 8 times out of 10 ? But to not be drawn for 5 times in a row ? But for 6 times in a row ? Thank you very much in advance !

Are all of the tickets returned after each draw, so that you always have a 5/6 chance of winning? Were you not drawn exactly 8 out of 10 times, winning the other 2 drawings?

Yes, 5/6 chance of winning. And yes 8 of 10 times I missed. (and I am not sure if it was a streak of 5 or 6 consecutive misses)

The streaks are easy. They're just (odds of missing)^#ofmisses, so (1/6)^5 and (1/6)^6.

I think this was already discussed just a few days ago.

For the first question (not to be drawn in 8 out of 10 cases) it involves the binomial probability distribution. (P[n,k]= C[n,k]*p^k*q^n-k ) I think is 1 / 53747,71 for the above question.

For the second, you have 2 distinctions: not to be drawn 5 times in a row from 5 trials or not to be drawn 5 times in a row in 10 trials or whatever. There are some calculators you can calculate each case.

I must add, these probabilities are apriori or before the event took place. If you had 10 draws and 8 times you didnt win, the probability for this is 1.