hortonelectric
hortonelectric
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Joined: May 22, 2015
May 22nd, 2015 at 2:15:40 PM permalink
Given the following 3 scenarios, what would be the house edge for baccarat?

Scenario 1: When a TIE occurs, any bets on player or dealer are marked a LOSS and the casino takes it.

Scenario 2: When a TIE occurs, any bets on player or dealer are RETURNED to the player as if they never occurred

Scenario 3: When a TIE occurs, any bets on player or dealer are UNABLE TO BE REMOVED AND WILL RESOLVE ON THE NEXT HAND, ASSUMING IT ISN'T ALSO A TIE

I have been struggling with this. I believe Scenario THREE is the most common ruleset and this is where 1.06/1.16 percent house edge that is typically calculated is applied.

However, for Scenario 1 and 2, it seems difficult to calculate and I'm not even sure how to do it.

Please help!
ThatDonGuy
ThatDonGuy
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Joined: Jun 22, 2011
May 22nd, 2015 at 6:32:18 PM permalink
Here's what I get, with an 8-deck shoe:

Player Bet Ties Lose: 0.446247 - 0.553753 = -0.107506 = 10.751%
Player Bet Ties Push: 0.446247 - 0.458597 = -0.01235 = 1.235%
Player Bet Ties Replay: 0.493176 - 0.506824 = -0.013648 = 1.365%

Banker Bet Ties Lose (no commission): 0.458597 - 0.541403 = -0.082806 = 8.281%
Banker Bet Ties Push: 0.458597 x 0.95 - 0.446247 = -0.01058 = 1.058%
Bank Bet Ties Replay: 0.506824 x 0.95 - 0.493176 = -0.011693 = 1.169%

Actually, I have never heard of rules set three being applied anywhere, although I am not much of a baccarat player. However, a number of people do consider "ties push" as "pretend ties never happen" when calculating house edge (wasn't this what we in computer science call a "holy war" at one point, where there are two ways to do something and the supporters of each one are quite fervent in their belief that they are correct), so this may be where the idea that "bets are unable to be removed after a tie" originates.
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