1x
2x
5x
10x
2 rolls
4 rolls.
So for one spin only one of these choices can win once the wheel stops on whichever spot it happens to land on. With a 1$ bet on 2x you will win 1$ * 2 =2$ win.
If I bet 1$ on 10x you would win 10$.
2 rolls and 4 rolls on this game triggers a bonus feature in which mr monopoly runs around the Hasbro monopoly board at which point a 1$ bet pays 1$-300$ depending on your luck for this particular spin.
Now I apologise my explanation of the game is probably super confusing but how can I explain to my mother that if you have 3$ to play with for the day and you place your 3$ on 1 spin spread out to where you have 1$ ----> on 2x
1$ -----> on 10x
1$ -----> on 2 rolls the wheel can only hit 1 outcome my mom says it's the same the house edge is not effected either way. Spreading The $3 out on one spin vs
1$ on 3 separate spins so spin #1 I bet 1$ on 2x
Spin #2 1$ on 10x
Spin #3 1$ on 2 rolls
She says it's the same thing as far as the house edge and RTP is concerned I said hello fuc&$# no it's not the same thing help me please!!!
I admit to not quite understanding your description of the game and i can't be bothered to research it...Quote: WifeslayerMy family has turned against me on this, I can't describe what I'm trying to get at here to them because my math skills are so poor. ...
Now I apologise my explanation of the game is probably super confusing but how can I explain to my mother that if you have 3$ to play with for the day and you place your 3$ on 1 spin spread out to where you have 1$ ----> on 2x
1$ -----> on 10x
1$ -----> on 2 rolls the wheel can only hit 1 outcome my mom says it's the same the house edge is not effected either way. Spreading The $3 out on one spin vs
1$ on 3 separate spins so spin #1 I bet 1$ on 2x
Spin #2 1$ on 10x
Spin #3 1$ on 2 rolls
She says it's the same thing as far as the house edge and RTP is concerned I said hello fuc&$# no it's not the same thing help me please!!!
... That said, AIUI, if the game is resolved on a per spin basis, then each bet type will have it's own distinct fixed house edge, It won't matter if you split your $3 into 3 bets, or lay it down in one bet of the same type. It will change the variance, but not the edge. Of course, spreading across multiple bet types might give a different overall house edge to any one of the contributing bet types.
-jason
There appear to be 52 spaces on the wheel besides the two Chance spaces which I'll ignore for now, of which:
15 are 2s
3 are 10s
3 are 2 Rolls
Doing it one spin at a time:
The RTP for the bet on 2 is 3 x 15/52 = 45/52
The RTP for the bet on 10 is 11 x 3/52 = 33/52
Let X be the amount you are expected to win on the two free rolls; the RTP for the bet on 2 Free Rolls is (X + 1) x 3/52
For one spin, the RTP is 3 x 15/52 + 11 x 3/52 + (X + 1) x 3/52, which is the same. As already pointed out, the variance might be different, but the RTP and the house edge are the same.
It may appear different because you're more likely to win one of the bets if they're made together, but keep in mind that you can't win more than one bet that way, while you can if they are separate bets.
Look at it from a roulette standpoint. Suppose you make 3 different bets - one on Low (i.e. 1-18), one on the 19-24 lines, and one on the 25-36 dozen. Does the house edge or RTP change between making those bets on different spins as opposed to all on a single spin?
My brain is still processing and trying to understand the variance change and not it being the house edge.
Thedon thank you again!
To help you get a grip on the variance thing, consider a fair wager on a coin flip...Quote: WifeslayerNice you went and checked out the game ! Thank you I was being decieved as you pointed out it may appear that you are winning more when the bets are packed into a single spin.
My brain is still processing and trying to understand the variance change and not it being the house edge.
Thedon thank you again!
Let's say you have $100 and two choices: Bet $100 on one wager of heads or Bet $1 on one hundred wagers of heads.
With the single wager, you will either win $100 or lose $100 with no other options. There will be a 50% probability of winning $100
But with the hundred small wagers, there will be 2^100 possible outcomes, only 1, extremely unlikely possibility of winning or losing $100 but lots of chances to roughly break even.
With the 100 small wagers, you would at least get the fun of playing 100 times. That's less likely with 1 wager.
The average return to player in both scenarios is the same, in this case 100% with no house edge in either case.
Note for the single wager, there is zero chance of breaking even, so it isn't even possible to get the average expected return.