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Calculating '21s' from a single deck....
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| January 17th, 2012 at 5:47:24 AM permalink | |
| NowTheSerpent Member since: Sep 30, 2011 Threads: 11 Posts: 278 |
The term you're looking for is permutations. While a combination denotes a specific way of selecting a specified number of elements at a time from a larger number of elements, a permutation denotes a way of arranging that specified number of elements. For example, the number of different two-pair-only hands in five-card poker is given by saying that, out of the thirteen ranks, three will be selected, two of those ranks in turn each selecting two of the four suits and one of them selecting one. The two-pair-only hand - single combination - you end up holding is, say Qh, Qd, 5d, 5c, 7s. While you may be dealt these cards one at a time in any of 5! = 120 possible sequences, the specific cards selected from the deck remain the same. Never maintain as merely a "humble" opinion that which you are not prepared to defend; If that which you hold can be rigorously supported, don't be so "humble" as to call it "your" opinion, for indeed its reality transcends and holds YOU. |
| January 17th, 2012 at 4:23:23 PM permalink | |
| IGC Member since: Jan 15, 2012 Threads: 1 Posts: 6 | LOL. I see the forum 'bug' has you. Sarcasm, MATE, is not appreciated. First of all, you stated ACE/KING and KING/ACE as being 1 not 2 - even though you just gave two. Probability maths needs to address whether the order is important or not, and in this case is it not important so therefore there are two ways to acheive the same outcome. Besides, this is an easy answer to find as its plastered all over the internet on math expert sites and gambling statistic sites - and they ALL claim 128/2652. But like you said, you're not a maths expert. But then again, Im not an English expert either and I think it was pretty clear that I was asking about three card combinations overall. But thanks anyway.... |
| January 17th, 2012 at 4:37:28 PM permalink | |
| Ibeatyouraces Member since: Jan 12, 2010 Threads: 18 Posts: 919 | Must be the John Patrick sites. I stick with my answer. Only 1 way to make ace/king of clubs, or any other 2 card hand no matter what card comes first. BTW, there are 22100 total possible 3 card hands but your math may find more. "Shut up Meg."
Peter Griffin, Family Guy |
| January 20th, 2012 at 4:12:16 PM permalink | |
| charliepatrick Member since: Jun 17, 2011 Threads: 2 Posts: 152 | Sometime ago, for a laugh and before seeing http://wizardofodds.com/games/three-card-blackjack/, I looked at the totals that were formed with three cards (assuming an Ace was 1 or 11) but ignoring the totals from the first two cards (if you had 20 you wouldn't really hit to get the three-card 21). For instance there are four ways to get 6 (being three 2s and deciding which suit to omit), since A23 would be considered as 16. 30 560 29 480 28 576 27 740 26 856 25 1040 24 1180 23 1384 22 1544 21 2012 20 1688 19 1640 18 1540 17 1448 16 1304 15 1172 14 984 13 828 12 620 11 200 10 136 9 92 8 48 7 24 6 4 |
| January 20th, 2012 at 5:54:44 PM permalink | |
| pacomartin Member since: Jan 14, 2010 Threads: 547 Posts: 6211 |
Are you actually arguing if the answer should be 128/2652 or 64/1326 ? Personally, I think you are both wrong. The correct answer is 32/663. Also acceptable is one in 20+23/32. Wine loved I deeply, dice dearly -Edgar, betrayed son of Gloucester in King Lear |
| January 20th, 2012 at 6:30:47 PM permalink | |
| Ibeatyouraces Member since: Jan 12, 2010 Threads: 18 Posts: 919 | Watch poker. There are EXACTLY 1326 possible 2 card starting hands in hold-em. Being dealt two cards in a single deck bj game is no different when shuffled every hand. "Shut up Meg."
Peter Griffin, Family Guy |
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