## Poll

16 votes (51.61%) | |||

12 votes (38.7%) | |||

5 votes (16.12%) | |||

2 votes (6.45%) | |||

9 votes (29.03%) | |||

3 votes (9.67%) | |||

5 votes (16.12%) | |||

5 votes (16.12%) | |||

10 votes (32.25%) | |||

7 votes (22.58%) |

**31 members have voted**

December 21st, 2020 at 10:28:16 PM
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Quote:ssho88

a) a = 2*(pi)^0.5/3^0.25 * r = 2.693547r

b) Total Area outside circle = 0.573249r^2

"That was too fast. Please go back to your seat and check your work."

BUT....

You are CORRECT!!!

(Sorry, just flashing back to high school there.)

What did the triangle say to the circle?

You're pointless!

December 22nd, 2020 at 4:47:42 PM
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A belated tannenbaum Tuesday...

Place each of the numbers from 1 to 10 on the tree ornaments so that every line adds up to the same number.

There are five lines, three lines containing four ornaments, one line with three ornaments, and one line with just two ornaments.

Place each of the numbers from 1 to 10 on the tree ornaments so that every line adds up to the same number.

There are five lines, three lines containing four ornaments, one line with three ornaments, and one line with just two ornaments.

Have you tried 22 tonight? I said 22.

December 22nd, 2020 at 7:42:39 PM
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Quote:GialmereA belated tannenbaum Tuesday...

Place each of the numbers from 1 to 10 on the tree ornaments so that every line adds up to the same number.

There are five lines, three lines containing four ornaments, one line with three ornaments, and one line with just two ornaments.

There are 3 rows and total of those 10 numbers is 55, so each row add up should be either 18, 17, 16 or 15. Only 18 is possible.

1

10 8

5 7 6

2 9 4 3

December 22nd, 2020 at 8:38:58 PM
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Quote:ssho88

There are 3 rows and total of those 10 numbers is 55, so each row add up should be either 18, 17, 16 or 15. Only 18 is possible.

1

10 8

5 7 6

2 9 4 3

Correct!

There's also a few mirror image variants that work.

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Have you tried 22 tonight? I said 22.

December 23rd, 2020 at 8:03:18 AM
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Simplify the following equation...

Have you tried 22 tonight? I said 22.

December 23rd, 2020 at 8:59:41 AM
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Quote:GialmereSimplify the following equation...

The first part is:

((X + A)(X - A) M + A^2 M) E

= M (X^2 - A^2 + A^2) E

= M E X^2

The left side of the second part is:

((R + X) / X + X / (R - X)) / (X / (R - X))

= ((R^2 - X^2 + X^2) / (X (R - X))) / (X / (R - X))

= R^2 / (X (R - X)) * (R - X) / X

= R^2 / X^2

The right side of the second part is:

4AS / 3 * (1 / (X ((E + Y)^2 - (E - Y)^2)) + 1 / (E ((Y + X)^2 - (Y - X)^2)) + 1 / (Y ((X + E)^2 - (X - E)^2)))

= 4AS / 3 * (1 / 4XEY + 1 / 4EYX + 1 / 4YXE)

= 4AS / 3 * 3/4 * 1/XEY

= AS / XEY

Subtract the right side of the second part from the left side, then multiply by Y:

Y (R^2 / X^2 - AS / XEY)

= Y (R^2 XEY - AS X^2) / (X^3 EY)

= (R^2 EY - ASX) / (X^2 E)

The product of the two parts is:

MEX^2 (R^2 EY - ASX) / (X^2 E)

= M (R^2 EY - ASX)

= MERRY - XMAS

December 23rd, 2020 at 4:37:56 PM
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Quote:ThatDonGuy

The first part is:

((X + A)(X - A) M + A^2 M) E

= M (X^2 - A^2 + A^2) E

= M E X^2

The left side of the second part is:

((R + X) / X + X / (R - X)) / (X / (R - X))

= ((R^2 - X^2 + X^2) / (X (R - X))) / (X / (R - X))

= R^2 / (X (R - X)) * (R - X) / X

= R^2 / X^2

The right side of the second part is:

4AS / 3 * (1 / (X ((E + Y)^2 - (E - Y)^2)) + 1 / (E ((Y + X)^2 - (Y - X)^2)) + 1 / (Y ((X + E)^2 - (X - E)^2)))

= 4AS / 3 * (1 / 4XEY + 1 / 4EYX + 1 / 4YXE)

= 4AS / 3 * 3/4 * 1/XEY

= AS / XEY

Subtract the right side of the second part from the left side, then multiply by Y:

Y (R^2 / X^2 - AS / XEY)

= Y (R^2 XEY - AS X^2) / (X^3 EY)

= (R^2 EY - ASX) / (X^2 E)

The product of the two parts is:

MEX^2 (R^2 EY - ASX) / (X^2 E)

= M (R^2 EY - ASX)

= MERRY - XMAS

Correct!

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Have you tried 22 tonight? I said 22.

December 25th, 2020 at 3:34:23 PM
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If G's puzzle from Dec 23 was too hard, perhaps this one will be more to your liking. What does it say?

It's not whether you win or lose; it's whether or not you had a good bet.

December 26th, 2020 at 10:22:40 AM
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My belated guess is

me^(rr y) = x-mas