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chevy
chevy
Joined: Apr 15, 2011
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December 21st, 2020 at 10:28:16 PM permalink
Quote: ssho88





a) a = 2*(pi)^0.5/3^0.25 * r = 2.693547r
b) Total Area outside circle = 0.573249r^2



"That was too fast. Please go back to your seat and check your work."

BUT....

You are CORRECT!!!

(Sorry, just flashing back to high school there.)




What did the triangle say to the circle?

You're pointless!

Gialmere
Gialmere
Joined: Nov 26, 2018
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December 22nd, 2020 at 4:47:42 PM permalink
A belated tannenbaum Tuesday...



Place each of the numbers from 1 to 10 on the tree ornaments so that every line adds up to the same number.

There are five lines, three lines containing four ornaments, one line with three ornaments, and one line with just two ornaments.
Have you tried 22 tonight? I said 22.
ssho88
ssho88 
Joined: Oct 16, 2011
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Gialmere
December 22nd, 2020 at 7:42:39 PM permalink
Quote: Gialmere

A belated tannenbaum Tuesday...



Place each of the numbers from 1 to 10 on the tree ornaments so that every line adds up to the same number.

There are five lines, three lines containing four ornaments, one line with three ornaments, and one line with just two ornaments.




There are 3 rows and total of those 10 numbers is 55, so each row add up should be either 18, 17, 16 or 15. Only 18 is possible.

1
10 8
5 7 6
2 9 4 3

Gialmere
Gialmere
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December 22nd, 2020 at 8:38:58 PM permalink
Quote: ssho88


There are 3 rows and total of those 10 numbers is 55, so each row add up should be either 18, 17, 16 or 15. Only 18 is possible.

1
10 8
5 7 6
2 9 4 3


Correct!

There's also a few mirror image variants that work.

-----------------------------

Have you tried 22 tonight? I said 22.
Gialmere
Gialmere
Joined: Nov 26, 2018
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December 23rd, 2020 at 8:03:18 AM permalink


Simplify the following equation...

Have you tried 22 tonight? I said 22.
ThatDonGuy
ThatDonGuy
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charliepatrickGialmere
December 23rd, 2020 at 8:59:41 AM permalink
Quote: Gialmere

Simplify the following equation...



The first part is:
((X + A)(X - A) M + A^2 M) E
= M (X^2 - A^2 + A^2) E
= M E X^2

The left side of the second part is:
((R + X) / X + X / (R - X)) / (X / (R - X))
= ((R^2 - X^2 + X^2) / (X (R - X))) / (X / (R - X))
= R^2 / (X (R - X)) * (R - X) / X
= R^2 / X^2

The right side of the second part is:
4AS / 3 * (1 / (X ((E + Y)^2 - (E - Y)^2)) + 1 / (E ((Y + X)^2 - (Y - X)^2)) + 1 / (Y ((X + E)^2 - (X - E)^2)))
= 4AS / 3 * (1 / 4XEY + 1 / 4EYX + 1 / 4YXE)
= 4AS / 3 * 3/4 * 1/XEY
= AS / XEY

Subtract the right side of the second part from the left side, then multiply by Y:
Y (R^2 / X^2 - AS / XEY)
= Y (R^2 XEY - AS X^2) / (X^3 EY)
= (R^2 EY - ASX) / (X^2 E)

The product of the two parts is:
MEX^2 (R^2 EY - ASX) / (X^2 E)
= M (R^2 EY - ASX)
= MERRY - XMAS

Gialmere
Gialmere
Joined: Nov 26, 2018
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December 23rd, 2020 at 4:37:56 PM permalink
Quote: ThatDonGuy



The first part is:
((X + A)(X - A) M + A^2 M) E
= M (X^2 - A^2 + A^2) E
= M E X^2

The left side of the second part is:
((R + X) / X + X / (R - X)) / (X / (R - X))
= ((R^2 - X^2 + X^2) / (X (R - X))) / (X / (R - X))
= R^2 / (X (R - X)) * (R - X) / X
= R^2 / X^2

The right side of the second part is:
4AS / 3 * (1 / (X ((E + Y)^2 - (E - Y)^2)) + 1 / (E ((Y + X)^2 - (Y - X)^2)) + 1 / (Y ((X + E)^2 - (X - E)^2)))
= 4AS / 3 * (1 / 4XEY + 1 / 4EYX + 1 / 4YXE)
= 4AS / 3 * 3/4 * 1/XEY
= AS / XEY

Subtract the right side of the second part from the left side, then multiply by Y:
Y (R^2 / X^2 - AS / XEY)
= Y (R^2 XEY - AS X^2) / (X^3 EY)
= (R^2 EY - ASX) / (X^2 E)

The product of the two parts is:
MEX^2 (R^2 EY - ASX) / (X^2 E)
= M (R^2 EY - ASX)
= MERRY - XMAS


Correct!
---------------------------

Have you tried 22 tonight? I said 22.
Wizard
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Wizard
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December 25th, 2020 at 3:34:23 PM permalink
If G's puzzle from Dec 23 was too hard, perhaps this one will be more to your liking. What does it say?

It's not whether you win or lose; it's whether or not you had a good bet.
chevy
chevy
Joined: Apr 15, 2011
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December 26th, 2020 at 10:22:40 AM permalink

My belated guess is

me^(rr y) = x-mas

Wizard
Administrator
Wizard
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December 26th, 2020 at 12:04:40 PM permalink
Quote: chevy


My belated guess is

me^(rr y) = x-mas



Where does the natural log fit into it?
It's not whether you win or lose; it's whether or not you had a good bet.

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