So expected value for Option 1 is .2 x 5 x 3.5 = 3.5
Expected value for Option 2 is 3 x .2 x 2 x 3.5 = 1.2 x 3.5 = 4.2
My question was, what is the difference in outcomes expected between taking 10 turns rolling 2 six sided dice vs. 10 turns rolling 1 twelve sided dice. If two players were competing against each other, which would have a higher total over 10 turns, and who would win the highest value in each of the individual turns?
Common sense. Two six sided dice have a minimum of 2 compared to a minimum of 1 for the 12 sided die.Quote: RobertrobertsThank you for your reply. I had another question about multi sided dice games. I was interested in the term "expected value".
My question was, what is the difference in outcomes expected between taking 10 turns rolling 2 six sided dice vs. 10 turns rolling 1 twelve sided dice. If two players were competing against each other, which would have a higher total over 10 turns, and who would win the highest value in each of the individual turns?
Quote: RobertrobertsThank you for your reply. I had another question about multi sided dice games. I was interested in the term "expected value".
My question was, what is the difference in outcomes expected between taking 10 turns rolling 2 six sided dice vs. 10 turns rolling 1 twelve sided dice. If two players were competing against each other, which would have a higher total over 10 turns, and who would win the highest value in each of the individual turns?
just substitute the new values into the same formula from above
10 turns with 2 six sided dice: 10 * 2 * 3.5 = 70
10 turns with 1 twelve sided die: 10 * 6.5 = 65