HeyMrDJ
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March 27th, 2018 at 2:03:33 AM permalink
There is a new online wheel game called Dreamcatcher

Its a bit like Big6, but possibly better.

You can see it in action here Probably not safe for work

It has the following

23 1 slots
15 2 slots
7 5 slots
4 10 slots
2 20 slots
1 40 slot

And

1 2x Multiplier slot
1 7x Multiplier slot

The good thing is, the multipliers can stack, so in the video you see it land on 7x and then the 2x multiplier for a 14x total multiplier, it then lands on the 5 slot for a total payout of 70x the bet.

My question is, how do you calculate the edge on this? It could keep hitting the multipliers and pay huge. Once it hits one multiplier, all bets are frozen by the way.
Guess who peed in my Cheerios? Romes did...
JB
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March 27th, 2018 at 5:30:19 AM permalink
( incorrect math stricken from the record )

If you bet on the 'X' spot, whose weight is 'W', the return is the following recursive equation:

(X * W/54) + (return * 2 * 1/54) + (return * 7 * 1/54)

If you call the return R, the above boils down to:

R = (XW + 9R) / 54

Let's get rid of the recursion. Multiply both sides by 54:

54R = XW + 9R

Subtract 9R from each side:

45R = XW

Divide both sides by 45:

R = XW / 45

So the return for each spot is its prize multiplied by its weight, divided by 45:

the 1 spot returns 23/45 = 51.1111%
the 2 spot returns 30/45 = 66.6666%
the 5 spot returns 35/45 = 77.7777%
the 10 spot returns 40/45 = 88.8888%
the 20 spot returns 40/45 = 88.8888%
the 40 spot returns 40/45 = 88.8888%

These numbers assume a fair wheel, which it looked like it was.
Last edited by: JB on Mar 27, 2018
HeyMrDJ
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March 27th, 2018 at 5:54:24 AM permalink
but does this allow for landing on 7x three times, then a winning number?
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JB
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March 27th, 2018 at 5:57:13 AM permalink
Yes, hence the recursion.
rsactuary
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March 27th, 2018 at 6:45:10 AM permalink
Why does it seem like the film is edited in between each spin?
HeyMrDJ
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March 27th, 2018 at 9:31:49 AM permalink
Quote: rsactuary

Why does it seem like the film is edited in between each spin?



So the 1 spot has a 49% house edge? That cant be right surely
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JB
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March 27th, 2018 at 10:21:30 AM permalink
( incorrect math stricken from the record )

There are 23 spots out of 54 total that land a 1. Before considering the multipliers, the return from this is 1 * 23 / 54 = 0.4259259

If you hit 2x and then the 1: this pays 2 * 1 with probability (1/54) * (23/54) for another 0.015775
If you hit 7x and then the 1: this pays 7 * 1 with probability (1/54) * (23/54) for another 0.05521262
If you hit 2x, 2x, 1: this pays 2 * 2 * 1 with probability (1/54) * (1/54) * (23/54) = another 0.000584261
If you hit 2x, 7x, 1: this pays 2 * 7 * 1 with probability (1/54) * (1/54) * (23/54) = another 0.002044912
If you hit 7x, 2x, 1: this pays 7 * 2 * 1 with probability (1/54) * (1/54) * (23/54) = another 0.002044912
If you hit 7x, 7x, 1: this pays 7 * 7 * 1 with probability (1/54) * (1/54) * (23/54) = another 0.007157191

As you can see, longer multiplier sequences can only increase the return by increasingly tiny amounts.

The total return, with every possible multiplier sequence factored in, is 23/45 = 0.511111
Last edited by: JB on Mar 27, 2018
CrystalMath
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JB
March 27th, 2018 at 11:57:53 AM permalink
Quote: JB

There are 23 spots out of 54 total that land a 1. Before considering the multipliers, the return from this is 1 * 23 / 54 = 0.4259259

If you hit 2x and then the 1: this pays 2 * 1 with probability (1/54) * (23/54) for another 0.015775
If you hit 7x and then the 1: this pays 7 * 1 with probability (1/54) * (23/54) for another 0.05521262
If you hit 2x, 2x, 1: this pays 2 * 2 * 1 with probability (1/54) * (1/54) * (23/54) = another 0.000584261
If you hit 2x, 7x, 1: this pays 2 * 7 * 1 with probability (1/54) * (1/54) * (23/54) = another 0.002044912
If you hit 7x, 2x, 1: this pays 7 * 2 * 1 with probability (1/54) * (1/54) * (23/54) = another 0.002044912
If you hit 7x, 7x, 1: this pays 7 * 7 * 1 with probability (1/54) * (1/54) * (23/54) = another 0.007157191

As you can see, longer multiplier sequences can only increase the return by increasingly tiny amounts.

The total return, with every possible multiplier sequence factored in, is 23/45 = 0.511111



This game actually pays on a "to one" basis, so the rtp is much higher than this.
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JB
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March 27th, 2018 at 12:51:41 PM permalink
Quote: CrystalMath

This game actually pays on a "to one" basis, so the rtp is much higher than this.


Ah, of course. I really need to stick to programming, it's so much easier than math.
FleaStiff
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March 27th, 2018 at 5:39:35 PM permalink
Quote: JB


the 10 spot returns 40/45 = 88.8888%
the 20 spot returns 40/45 = 88.8888%
the 40 spot returns 40/45 = 88.8888%

Then there is no advantage to betting more than ten dollars except that if you do win you get more money but I fail to see how a casino can make money this way.
CrystalMath
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March 27th, 2018 at 6:33:11 PM permalink
Quote: FleaStiff

Then there is no advantage to betting more than ten dollars except that if you do win you get more money but I fail to see how a casino can make money this way.



These RTPs are incorrect because the game pays on a “to one” basis rather than a “for one.” Also, you don’t need to bet $10 on the 10 spot. It just means you get paid 10 to 1 on a win.
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CrystalMath
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March 27th, 2018 at 7:29:18 PM permalink
Quote: FleaStiff

Then there is no advantage to betting more than ten dollars except that if you do win you get more money but I fail to see how a casino can make money this way.



These RTPs are incorrect because the game pays on a “to one” basis rather than a “for one.” Also, you don’t need to bet $10 on the 10 spot. It just means you get paid 10 to 1 on a win.
I heart Crystal Math.
JB
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March 27th, 2018 at 8:45:29 PM permalink
A simulation reveals that the bets return somewhere between 90% and 97%, so I'll leave it there and let someone smarter than me work out the correct math.
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