usarobert
usarobert
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February 10th, 2011 at 3:18:02 AM permalink
Hello,

Can somebody explain me, why the House Edge in a 2 Deck Blackjack game is lower then with 6 Decks ?
The Rules are assumed to be the same, and it would be played with a stratey .. no card counting.

Thanks in advance

usarobert
mkl654321
mkl654321
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February 10th, 2011 at 10:12:28 AM permalink
The more decks there are in play, the harder it is to get a blackjack.
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rdw4potus
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February 10th, 2011 at 10:51:39 AM permalink
...and the easier it is for the dealer to not-break.
"So as the clock ticked and the day passed, opportunity met preparation, and luck happened." - Maurice Clarett
teddys
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February 10th, 2011 at 11:09:17 AM permalink
Better chance for you to get a blackjack, your double-downs will work slightly more often, and the dealer will bust slightly more often.
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soulhunt79
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February 10th, 2011 at 11:44:11 AM permalink
Even if you aren't counting, there is still a very slight edge in knowing your 2 cards. If you have a 5 and a 6, the odds of the next card being a 10 are slightly higher with fewer decks.
usarobert
usarobert
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February 11th, 2011 at 2:08:28 AM permalink
hmm .. I don't understand why ..
every Deck has 4 Aces and 16 Cards at the Value of 10 ..
So if I have one Deck the probability of getting an Aces is 4 out of 52 or 7,69% getting a Card with Value 10 is 16 out of 52 or 30,77%.

If I now increase the Number of Decks the Number of Aces an 10s will also go up.
Lets say 4 Decks
Aces is 16 out of 208 or 7,69 % (!!)
10s is 64 out of 208 or 30,77% (!!)
the same

so why is the odd different to get a 10 if it are 2 Decks or 4 or 6 Decks ??
weaselman
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February 11th, 2011 at 4:22:18 AM permalink
Quote: usarobert


the same


Only when you are looking at the first card. But suppose you already got an ace. What is the probability of getting a ten now?
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boymimbo
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February 11th, 2011 at 5:47:33 AM permalink
Let's say that the dealer has a 10 on top. What are the odds in a double deck game that s/he has another 10?

Answer is 31 / 103. = 30.10 percent

For six decks, the answer is 95 / 311 = 30.55 percent.

That .45 percent affects house advantage. The tables take into accounts the effect of card removal and the strategy changes to show the change in odds as a result of it.

The thing to know is that the more you know about the cards played, the more information you have to change your strategy and change the game to your advantage. Dealers have a hard set of rules to abide to. Players don't.
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mkl654321
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February 11th, 2011 at 10:32:28 AM permalink
Quote: usarobert

hmm .. I don't understand why ..
every Deck has 4 Aces and 16 Cards at the Value of 10 ..
So if I have one Deck the probability of getting an Aces is 4 out of 52 or 7,69% getting a Card with Value 10 is 16 out of 52 or 30,77%.

If I now increase the Number of Decks the Number of Aces an 10s will also go up.
Lets say 4 Decks
Aces is 16 out of 208 or 7,69 % (!!)
10s is 64 out of 208 or 30,77% (!!)
the same

so why is the odd different to get a 10 if it are 2 Decks or 4 or 6 Decks ??



If you are playing single deck, and you get dealt an Ace, the chance of getting a blackjack is now 16/51. If you were playing double deck, the chance of getting a blackjack would now be 32/103--a smaller number. Also, you could look at it like this--if you had a "quarter deck" consisting only of the spades 2-A, then you would have a 1/3 chance of getting a blackjack after being dealt an Ace--and 1/3 is a larger number than either 16/51 or 32/103.

The calculation would be similar for the chance of getting a blackjack after being dealt a face card. The reason is, removing the first card from the deck/shoe has a decreasing effect as the number of decks increases.
The fact that a believer is happier than a skeptic is no more to the point than the fact that a drunken man is happier than a sober one. The happiness of credulity is a cheap and dangerous quality.---George Bernard Shaw
P90
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February 11th, 2011 at 11:34:41 AM permalink
There are other considerations in play. Multiple decks have a considerably greater chance of delivering a pair (up to 30% difference). Which are favorable in most cases.
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mkl654321
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February 11th, 2011 at 6:25:04 PM permalink
Quote: P90

There are other considerations in play. Multiple decks have a considerably greater chance of delivering a pair (up to 30% difference). Which are favorable in most cases.



Maybe so, but the effect isn't that large or that favorable. With many first cards, you don't WANT another one of the same rank: 22, 33, 44, 66, 77, 88 are all bad hands, made less bad by the ability to split pairs, but still not hands you want.
The fact that a believer is happier than a skeptic is no more to the point than the fact that a drunken man is happier than a sober one. The happiness of credulity is a cheap and dangerous quality.---George Bernard Shaw
P90
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February 11th, 2011 at 7:33:00 PM permalink
Perhaps, but neither is 78 any better than 77. Not getting the same card doesn't yet mean you'll get a better one. The pair card is the worst possible one only for 88. And with 5 and T (comprising 5/13 of all cards), you actively want another one, it being second only to 6 and Ace respectively.
Overall, the pair card is neither better nor worse than the average on its own, but gives you a shot at splitting.
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Ibeatyouraces
Ibeatyouraces
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March 1st, 2011 at 10:12:23 AM permalink
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DUHHIIIIIIIII HEARD THAT!
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