tupp
Joined: Feb 9, 2012
• Posts: 519
June 19th, 2012 at 10:42:54 PM permalink
Quote: JyBrd0403

D'alembert the Martingale 60% progression.

Or, you could Labouchere the Fibonacci.
JyBrd0403
Joined: Jan 25, 2010
• Posts: 548
June 19th, 2012 at 11:01:20 PM permalink
Quote: tupp

Or, you could Labouchere the Fibonacci.

LOL. Thanks, tupp. Couldn't just let the novelty game win outright.
JyBrd0403
Joined: Jan 25, 2010
• Posts: 548
June 20th, 2012 at 12:08:23 PM permalink
Somehow, I knew there wasn't going to be much interest in a betting system that can beat an HE game on this forum. There's another thread where a simulation showed the D'Alembert wins outright against a 50/50 game of chance, and I don't remember any kind of math being done on that, at all. Does the D'Alembert even work on a 50/50 game, mathematically?

Since, the term outright seems to be a mystery here. I'll give you a scenario.

"I had a nickel (That's five hundred dollars) on a pony (a horse) to show in the 5th (this means the 5th race). The damn thing won outright. (Means the horse won the race. This is also a funny joke. You laugh here. He's upset he didn't bet the horse to win)." They probably had the damn thing juiced up (means they gave the horse an illegal substance to make it run faster, also a funny joke, you laugh here). I should have dropped a dime(should have bet one thousand dollars) on her (does not indicate the sex of the horse, horses are commonly referred to as female). (this is also a funny sentence, you laugh here)."

Funny way of talking gamblers have isn't it. You see a lot of it on this forum.
rdw4potus
Joined: Mar 11, 2010
• Posts: 6610
June 20th, 2012 at 12:22:34 PM permalink
Quote: JyBrd0403

Somehow, I knew there wasn't going to be much interest in a betting system that can beat an HE game on this forum.

It can't beat the HE. You haven't done anything to change the HE, so you don't beat the HE. It's a constant.
"So as the clock ticked and the day passed, opportunity met preparation, and luck happened." - Maurice Clarett
mustangsally
Joined: Mar 29, 2011
• Posts: 1998
June 20th, 2012 at 12:30:45 PM permalink
removed
silly
Sally
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buzzpaff
Joined: Mar 8, 2011
• Posts: 5328
June 20th, 2012 at 12:35:08 PM permalink
I have a horse tomorrow going off at 20 to 1. Since the race doesn't start till 3:15 I think he is a lock to win !
guido111
Joined: Sep 16, 2010
• Posts: 707
June 20th, 2012 at 12:40:13 PM permalink
Quote: JyBrd0403

15% of the winnings sound about right? or, is that too high?

I say it is just right.
But you should pay at least 85% of the losses too. What, you want NO risk!

As a matter of fact, send me \$10,000 and I will pay you 50% over any winnings of \$5,000.
I will play just as you have outlined in this tread and will offer the Wizard also 50% of the winnings to watch and record the spins and wagers.

Then a big dinner to celebrate after.

Enjoy!
JyBrd0403
Joined: Jan 25, 2010
• Posts: 548
June 20th, 2012 at 12:43:24 PM permalink
Quote: mustangsally

You will find out that your system does not win outright in single 0 roulette.
Once in the positive it will be there only for a short while. Then into the negative to never return to the positive.

I have found it works way better in Craps with and without odds on the line bets.
Wake up and do the work yourself.
That way, you can trust yourself and no one else.

Your method, and your variants, that can easily be simulated in Excel also has a house edge on every win and loss.

Here is a graph showing the average of 10,000 sessions playing your first method with an unlimited bankroll. Total casino credit.
Does not look to me you will ever get back into the black. Downhill slide all the way.

That's not for the D'Alemberting of the Martingal, right?. That wins outright. That's for the 50% trinket I threw out there, right? Just trying to show how to keep the bankroll down. Did you figure out what needs to be changed to make it win?

So, that means there is math showing the D'alembert wins outright on a 50/50 game?
mustangsally
Joined: Mar 29, 2011
• Posts: 1998
June 20th, 2012 at 12:50:24 PM permalink
Quote: JyBrd0403

That's not for the D'Alemberting of the Martingal, right?. That wins outright. That's for the 50% trinket I threw out there, right? Just trying to show how to keep the bankroll down. Did you figure out what needs to be changed to make it win?

So, that means there is math showing the D'alembert wins outright on a 50/50 game?

Exactly as you instructions say.
UP 2X on a loss, and after a win 0.5 times on a win and same bet with a 0 spin.

I used unlimited casino credit, meaning NO bankroll was required.
Some bets and losses were so astronomical large that could never be made in a casino BTW.

You have NO PROOF your method wins outright.

It does not and never will according to those who have shown some results.

Time for you to show the proof.

We are all waiting and can wait a long time.

Sally
I Heart Vi Hart
mustangsally
Joined: Mar 29, 2011
• Posts: 1998
June 20th, 2012 at 12:52:25 PM permalink
Quote: JyBrd0403

So, that means there is math showing the D'alembert wins outright on a 50/50 game?

SN Ethier in his Doctrine of Chances book, Betting System chapter,
shows the math and proofs for 6 different popular betting systems.

From page 295

"If we also assume unlimited credit and no house limit (as is not typical),
the martingale, Fibonacci, and Labouchere systems are infallible, while
the other three systems are not" (Oscar, d’Alembert, Blundell)

I say the math does not lie and Mr. Ethier's math speaks for itself.

infallible = wins outright
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