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Pinochle probability question
| November 24th, 2011 at 5:25:30 AM permalink | |
| bettheodds Member since: Nov 24, 2011 Threads: 3 Posts: 3 | Me and the guys were playing pinochle and two of us didn't have a marriage (any king or queen combo of the same suit) on the same deal. We started talking about the odds of this happening. This is how we play... 80 cards J-Q-K-10-A only 4 suits 4 of each card i.e. J-Q-K-10-A x4 in each of the suits. We deal 20 cards each to all 4 players Love to know the odds!! Thanks!! |
| November 26th, 2011 at 10:49:15 AM permalink | |
| EdCollins Member since: Oct 21, 2011 Threads: 3 Posts: 24 | I estimate the probability of <i>having </i> a marriage in any given hand to be about 98.9% (.989) Thus, the approximate odds of <i>not </i> having a marriage in two hands is about .012% (.00012)... about 1 time every 10,000 deals. I'm sure the exact percentages are not off by much. |
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