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Poker Math
| May 5th, 2011 at 7:01:48 AM permalink | |
| urbanmk Member since: May 5, 2011 Threads: 1 Posts: 2 | 2 Players (A and B) Each player holds 5 cards Player A holds 4 aces and a 2 of hearts Player B can beat the hand of Player A with a straight flush How probable is the following event F: Player B has a straight flush Pr[F] = |F| / |Ω| = (3 * 8 + 7) / ((52 - 5) over 5)= 31 / 1533939 = 2.02 * 10^(-5) Is the above answer correct? EDIT: the term ((52 - 5) over 5) should probably be combin((52 - 5), 5). I do not know the exact notation. |
| May 5th, 2011 at 7:21:24 AM permalink | |
| Doc Member since: Feb 27, 2010 Threads: 21 Posts: 2825 | With your edit, it looks good to me. This is actually the conditional probability Pr[F/A], where A is the fact that player A has that specific hand. |
| May 9th, 2011 at 5:11:15 AM permalink | |
| urbanmk Member since: May 5, 2011 Threads: 1 Posts: 2 | Thank you for your answer! |
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