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5 Card Stud w One Fully Wild Joker
| April 20th, 2011 at 7:55:47 AM permalink | |
| JLFearless Member since: Apr 20, 2011 Threads: 1 Posts: 1 | I'd like to know the math behind figuring the number of Wild combinations for each Pair (2 of a Kind). I realize that for many of the lower pairs, there are no Wild combinations. For example, if the hand is 3H,3C,4D,7H,9S then there are no possibilities of making a Pair of 3's if the Joker were to replace any of the cards. I need the math broken down to the point to where I can calculate each possible pair, and then, based on percentages, divide the possible pairs. For example, I may divide the pairs into "Jacks or Better" and "10's or lower" OR "9's or Better" and "8's or lower" |
| April 20th, 2011 at 9:04:27 AM permalink | |
| DJTeddyBear Member since: Nov 2, 2009 Threads: 105 Posts: 5727 | As I recently found out, and has been confirmed by MathExtremist, once wilds are involved, the easiest / best method is to simply cycle thru every possible combination and evaluate them individually. Superstitions are silly, childish, irrational rituals, born out of fear of the unknown.
But how much does it cost to knock on wood? |
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