3 votes (13.63%) | |||

2 votes (9.09%) | |||

14 votes (63.63%) | |||

3 votes (13.63%) |

**22 members have voted**

January 10th, 2017 at 6:36:27 PM
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The solution to each equation is the product of the two numbers plus the smaller one. The order of the equations is irrelevant.

1 x 4 + 1 = 5

2 x 5 + 2 = 12

3 x 6 + 3 = 21

8 x 11 + 8 = 96

January 10th, 2017 at 11:53:51 PM
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Using the subtotal method:

x+y = f(x,y) = SUM[x, y, f(x-1, y-1)] where X > 0 OR Y > 0

-3+0 = -3

-2+1 = -1-3 = -4

-1+2 = 1-4 = -3

0+3 = 3-3 = 0

1+4 = 5+0 = 5

2+5 = 7+5 = 12

3+6 = 9+12 = 21

4+7 = 11+21 = 32

5+8 = 13+32 = 45

6+9 = 15+45 = 60

7+10 = 17+60 = 77

8+11 = 19+77 = 96

Using f(x,y) = x*(y+1) method:

f(8,11) = 8*(11+1) = 8*12 = 96

Like ME said -- there are many formulas that lead to the same answer....or that at least follow the pattern.

BTW, 5 does not exist in base 5.

5 in decimal is 10 in base-5: 1*5^1 + 0*5^0 Just like 2 in decimal is 10.

x+y = f(x,y) = SUM[x, y, f(x-1, y-1)] where X > 0 OR Y > 0

-3+0 = -3

-2+1 = -1-3 = -4

-1+2 = 1-4 = -3

0+3 = 3-3 = 0

1+4 = 5+0 = 5

2+5 = 7+5 = 12

3+6 = 9+12 = 21

4+7 = 11+21 = 32

5+8 = 13+32 = 45

6+9 = 15+45 = 60

7+10 = 17+60 = 77

8+11 = 19+77 = 96

Using f(x,y) = x*(y+1) method:

f(8,11) = 8*(11+1) = 8*12 = 96

Like ME said -- there are many formulas that lead to the same answer....or that at least follow the pattern.

BTW, 5 does not exist in base 5.

5 in decimal is 10 in base-5: 1*5^1 + 0*5^0 Just like 2 in decimal is 10.

"should of played 'Go Fish' today ya peasant" -typoontrav

January 11th, 2017 at 10:16:02 PM
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I think people are overthinking the problem. Sometimes you just have to strike the nail on the head. The answer is 40. Just my opinion.

January 12th, 2017 at 6:44:07 AM
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if there is no official answer, then this math exercise is perfect for the Millennials. Everybody is right and and we all get a trophy for participating!

"We thank with brief thanksgiving
Whatever gods may be
That no man lives forever,
That dead men rise up never"
Nor any gambler the long run see ever
........apologies to Swinburne for that last line

January 12th, 2017 at 6:50:39 AM
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https://www.youtube.com/watch?v=-HFwok9SlQQQuote:odiousgambitif there is no official answer, then this math exercise is perfect for the Millennials. Everybody is right and and we all get a trophy for participating!

Playing it correctly means you've already won.

January 12th, 2017 at 8:37:44 AM
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96.

Each number of the right side of the equation equals x*(y+1), where x is the first number and y is the second.

8*(11+1) = 96

It's not whether you win or lose; it's whether or not you had a good bet.

January 12th, 2017 at 8:40:07 AM
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Quote:RSUsing the subtotal method:

x+y = f(x,y) = SUM[x, y, f(x-1, y-1)] where X > 0 OR Y > 0

-3+0 = -3

-2+1 = -1-3 = -4

-1+2 = 1-4 = -3

0+3 = 3-3 = 0

1+4 = 5+0 = 5

2+5 = 7+5 = 12

3+6 = 9+12 = 21

4+7 = 11+21 = 32

5+8 = 13+32 = 45

6+9 = 15+45 = 60

7+10 = 17+60 = 77

8+11 = 19+77 = 96

Using f(x,y) = x*(y+1) method:

f(8,11) = 8*(11+1) = 8*12 = 96

Like ME said -- there are many formulas that lead to the same answer....or that at least follow the pattern.

Thanks for making me feel less than knowledgable. I just looked for a pattern and came up with 96.

January 13th, 2017 at 3:32:13 AM
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Quote:Romeshttps://www.youtube.com/watch?v=-HFwok9SlQQ

[video says there is no 'Millennials' generation ]

I may be stepping on some toes to rag on the M-gen, so from now on I will pick on Generation Z ....... LOL

"We thank with brief thanksgiving
Whatever gods may be
That no man lives forever,
That dead men rise up never"
Nor any gambler the long run see ever
........apologies to Swinburne for that last line