What is the house advantage at Delaware Park Casino on there Black Jack game????

I can try to walk through an example. (someone should check my math...)

Say you're alone at the table, and the dealer has just had you cut a new shoe.

Say your first card is an X and the dealer's first card is a Y. The odds that your second card is an X are ((6*4)-1)/((52*6)-2)=23/310. So there's a 7.5% chance that you'll pair your first card. You'll only want to split a fraction of those paired combinations, but I have ignored that for this example. I have also ignored the fact that even during the times you'll want to split, splitting is only marginally beneficial.

The odds of getting a 3rd X are ((6*4)-2)/((52*6)-3)=22/309, and the odds of getting a 4th paired card are ((6*4)-3)/((52*6)-4)=21/308. The odds of getting a hand to split 3 times into 4 hands are 23/310*22/309*21/308=.036%, or 1:2750 hands.

The odds of getting 5 matched cards are .00036*((6*4)-4)/((52*6)-5)=.00036*(20/307)=.00234% or 1:42600, and the odds of 6 matched cards are .0000234*((6*4)-5)/((52*6)-6)=.0000234*(19/306)=.000145% or 1:688000.

So having the right to split to 5 hands instead of 4 will only affect your play 1 in 42500 hands (1 in 14 hands when you already have 4 matched cards.)

The rarity of the times that you'll have 5 cards to split is what made me say that the infinite splitting would only help you a tiny bit.

RDW4POTUS I found out two more variables at Delaware Park Casino
they us a continuos shuffler and player cannot split 10's

Quote: rdw4potus

I can try to walk through an example. (someone should check my math...)

http://wizardofvegas.com/forum/gambling/blackjack/2036-probability-of-split-hands-infinite-deck/
This is from ininite decks and only to 4 hands:
1 hand = 12/13
2 hands = 144/2197
3 hands = 3456/371293
4 hands = 769/371293
Or 1 in 482 hands can be split into 4 hands.

Is this for the aces 3 hands for a total of 4 what about the unlimited splits what do i do there and how does the continuous shuffler effect the house advantage.

Quote: PlayBJ

Is this for the aces 3 hands for a total of 4 what about the unlimited splits what do i do there and how does the continuous shuffler effect the house advantage.

A continuous shuffler lowers the house edge. Only 1 in 6277 hand will end up as aces split to 4 hands. The differance in HE from spliting to 4 hands and unlimmited spliting is very small (less than .01% is my guess). Overall I get a house edge of 0.26197%

Hi Miplet,

Thanks for the reply with all the rules in place at Delaware Park you get .26197% HE I am way off

6 deck +0.54
double down on any cards -0.24
double down after spliting pairs -0.14
late surrender -0.06
re - split aces -0.06


total 0.04

Quote: PlayBJ

Hi Miplet,

Thanks for the reply with all the rules in place at Delaware Park you get .26197% HE I am way off

6 deck +0.54
double down on any cards -0.24
double down after spliting pairs -0.14
late surrender -0.06
re - split aces -0.06
draw to split aces -0.14


total -0.10

I don't understand what you're doing here. How are you getting those adjustments, and why are you starting from 0? Are you sure there's no native house advantage before you start adjusting?

Also, your original set of rule stipulations said that hitting split aces was not allowed. Can you actually draw to split aces in the game at Delaware Park? That would lower the HA quite a bit from the .26197% to .08432%.

Sorry rdw4potus I edited the rules as I remembered them no draw to split aces.

with a house edge of .26197 and a customer using perfect basic strategy and card counting is the edge in my favor with a six deck hand shuffled game.

Quote: PlayBJ

with a house edge of .26197 and a customer using perfect basic strategy

No.

Quote:

card counting

Maybe.