New Passline odds for dice (craps)

I want to make a new formula for craps. Please tell me how to construct this pass line formula.
Rules:

A) 3 and 7 win on the come out roll (nothing loses)

B) all other numbers become points: 2,4,5,6,8,9,10,11,12 and must repeat before a 3 or 7

C) 3 and 7 lose

Thank you for a great website.

Quote: sanstar

Rules:
A) 3 and 7 win on the come out roll (nothing loses)

B) all other numbers become points: 2,4,5,6,8,9,10,11,12 and must repeat before a 3 or 7

C) 3 and 7 lose

Fun with numbers at the end of a workday.

The HA = 8/36 + 2/36 * (1/9 - 8/9) + 2/36 * (2/10 - 8/10) + 6/36 (3/11-8/11) + 8/36 (4/12-8/12) + 10/36 (5/13 - 8/13)
= 8/36 - 14/324 - 12/360 - 30/396 - 32/432 - 30/468
= 2/9 - 7/162 - 1/30 - 5/66 - 2/27 - 5/78
= -.06826 = 6.826%

This won't work -- worst table at the casino.

Just make the 3 not lose after the Come Out. That would make it slightly different from Crapless Craps, since 3 can't be a point, but it would have odds more in line with regular craps because of the 3 winning on the Come out. (Could just as easily still be the 11 for ease of understanding for players.)